Json to M3U (Specific case)

converter.scala

import org.json4s.DefaultFormats
import org.json4s.JsonAST.JValue
import org.json4s.jackson.JsonMethods._

case class Channel(name: String, ch: String)

case class Category(id: String)

object JsonM3uTransformer extends App {

  implicit val formats = DefaultFormats

  val packListUrl = "xxx"

  def getChannelListFromPackUrl(id: String) = "yyy"

  def writeToFile(content: String) = {
    import java.io._
    val pw = new PrintWriter(new File("/tmp/test.m3u"))
    pw.write(content)
    pw.close
  }

  def generateM3UFromPack(list: List[Channel]): String = {

    list match {
      case Nil => ""
      case ::(head, tl) =>
        (s"""#EXTINF:-1,##===== ${head.name} =====##
            |${head.ch}""".stripMargin :: tl.map { channel =>
          s"""#EXTINF:-1,${channel.name}
             |${channel.ch}
       """.stripMargin
        }).mkString("\n")
    }

  }

  def get(url: String) = scala.io.Source.fromURL(url).mkString

  def getPackList = {
    val content = parse(get(packListUrl), false)

    (content \ "bouquets").extract[List[JValue]].map { content =>
      content.extract[Category]
    }
  }

  def getChannelListFromPack(id: String) = {
    val content = parse(get(getChannelListFromPackUrl(id)), false)

    (content \ "channels")
      .extract[List[JValue]]
      .map { content =>
        content.extract[Channel]
      }
      .filter { channel =>
        Option(channel.name).isDefined
      }
  }

//  val result = getPackList
  val result =
    ("#EXTM3U" :: (getPackList ::).map(cat => generateM3UFromPack(getChannelListFromPack(cat.id))))
      .mkString("\n")
  writeToFile(result)
  println(result)

}

Hello Elarib - Need your help in using this above script. json to m3u.

I have a json file which needs to be converted to m3u file. Can you help me and tell me to how do it. If possible if you have a workflow please assist.

https://gist.githubusercontent.com/naveenland4/414fde03d11bc824bc764984bc3067a6/raw/ch.json

Thanks
Naveen