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elegantcoder/extract_korean_initials.rb

Last active July 22, 2018 14:44
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extract_korean_initials.rb
# 삼성전자 => ㅅㅅㅈㅈ, 유안타제3호스팩 => ㅇㅇㅌㅈ3ㅎㅅㅍ
def extract_korean_initials(keyword)
initials = ['ㄱ', 'ㄲ', 'ㄴ', 'ㄷ', 'ㄸ', 'ㄹ', 'ㅁ', 'ㅂ', 'ㅃ', 'ㅅ', 'ㅆ', 'ㅇ', 'ㅈ', 'ㅉ', 'ㅊ', 'ㅋ', 'ㅌ', 'ㅍ', 'ㅎ']
# hangul_range = '가'..'힣'
hangul_first = 44032 # '가'.ord
size = 588 # '까'.ord - '가'.ord
keyword.split('').collect do |k|
k_char_code = k.ord
initials[(k_char_code - hangul_first) / size] || k
end
.join('')
end
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@fallroot 이건 대단히, 너무 간단한걸요!?

감사합니다 ㅎㅎㅎ

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