[프로그래머스] 다음 큰 숫자

next_01.js

//solution 01
function solution(n) {
    function cnt(number) {
        return number.toString(2)
                     .match(/1/g)
                     .length;
    }
    
    const n_cnt = cnt(n);
    let start = n;
    
    do {
        start++;
        if(cnt(start) == n_cnt){
            return start;
        }
    } while(true)
}

next_02.js

//solution 02
function solution(n) {
    function cnt(number) {
        return number.toString(2)
                     .match(/1/g)
                     .length;
    }
    
    const n_cnt = cnt(n);
    let start = n+1;
    
    while(cnt(start) != n_cnt) {
        start++;
    }
    return start;
}

next_03.js

//solution 03
function solution(n) {
    function cnt(number) {
        let temp = [];
        
        do {
            temp.push(number%2);
            number = Math.floor(number/2);
        } while(number > 0)
        
        return temp.join('').match(/1/g).length;
    }
    
    
    const n_cnt = cnt(n);
    let start = n;
    
    do {
        start++;
        if(cnt(start) == n_cnt){
            return start;
        }
    } while(true)
}

next_04.js

//solution 04
function solution(n) {
    function cnt(number) {
        return number.toString(2)
                     .split('')
                     .filter((el) => el == 1)
                     .length;
    }
    
    const n_cnt = cnt(n);
    let start = n + 1;

    for(start;  ; start++){
        if(cnt(start) == n_cnt){
            return start;
        }
    }
}