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Python nested function overhead
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| import timeit | |
| t1 = timeit.Timer("doit()", """ | |
| def doit(): | |
| def foo(l): | |
| return [x**2 for x in l] | |
| def bar(l): | |
| return [x**2 for x in l] | |
| l = [x for x in range(1000)] | |
| foo(l) | |
| bar(l) | |
| """) | |
| t2 = timeit.Timer("doit()", """ | |
| def foo(l): | |
| return [x**2 for x in l] | |
| def bar(l): | |
| return [x**2 for x in l] | |
| def doit(): | |
| l = [x for x in range(1000)] | |
| foo(l) | |
| bar(l) | |
| """) | |
| print(t2.repeat(10, 1000)) |
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