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@emmahsax
Last active January 11, 2024 20:01
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Pluralizing English words according to all pluralizing rules!

Easily Pluralizing English Words in Go

This code makes it easy to pluralize words based off of English pluralizing rules.

$ go run main.go
2 balls
1 boy
3 foxes
2 babies
1 leaf
3 knives
2 cats
1 dress
package main
import (
"fmt"
"strings"
)
func pluralize(word string, count int) string {
if count == 1 {
return word
}
lastChar := word[len(word)-1]
lastTwoChars := word[len(word)-2:]
switch {
case lastChar == 's' || lastChar == 'x' || lastChar == 'z' ||
(lastTwoChars == "ch" || lastTwoChars == "sh"):
return word + "es"
case lastTwoChars == "ay" || lastTwoChars == "ey" || lastTwoChars == "oy" || lastTwoChars == "uy":
return word + "s"
case lastChar == 'y' && !isVowel(word[len(word)-2]):
return word[:len(word)-1] + "ies"
case lastChar == 'y':
return word + "s"
case lastTwoChars == "fe" && len(word) > 2:
return word[:len(word)-2] + "ves"
case lastChar == 'f':
return word[:len(word)-1] + "ves"
default:
return word + "s"
}
}
func isVowel(char byte) bool {
return strings.ContainsAny(string(char), "aeiouAEIOU")
}
func main() {
word1 := "ball"
word2 := "boy"
word3 := "fox"
word4 := "baby"
word5 := "leaf"
word6 := "knife"
word7 := "cat"
word8 := "dress"
count1 := 2
count2 := 1
count3 := 3
fmt.Printf("%d %s\n", count1, pluralize(word1, count1)) // prints "2 balls"
fmt.Printf("%d %s\n", count2, pluralize(word2, count2)) // prints "1 boy"
fmt.Printf("%d %s\n", count3, pluralize(word3, count3)) // prints "3 foxes"
fmt.Printf("%d %s\n", count1, pluralize(word4, count1)) // prints "2 babies"
fmt.Printf("%d %s\n", count2, pluralize(word5, count2)) // prints "1 leaf"
fmt.Printf("%d %s\n", count3, pluralize(word6, count3)) // prints "3 knives"
fmt.Printf("%d %s\n", count1, pluralize(word7, count1)) // prints "2 cats"
fmt.Printf("%d %s\n", count2, pluralize(word8, count2)) // prints "1 dress"
}
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