Created
January 27, 2017 08:58
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Calculate e (euler's number), as long as you want
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length = 50 | |
n = 2 | |
first_numerator = 3 | |
first_denominator = 1 | |
second_numerator = 8 | |
second_denominator = 3 | |
result = [] | |
for i in xrange(length): | |
x = n | |
y = n + 1 | |
n = n + 1 | |
old_second_numerator = second_numerator | |
old_second_denominator = second_denominator | |
second_numerator = x * first_numerator + y * second_numerator | |
second_denominator = x * first_denominator + y * second_denominator | |
first_numerator = old_second_numerator | |
first_denominator = old_second_denominator | |
a = first_numerator / first_denominator | |
b = second_numerator / second_denominator | |
while a == b: | |
result.append(a) | |
first_numerator = 10 * (first_numerator % first_denominator) | |
second_numerator = 10 * (second_numerator % second_denominator) | |
a = first_numerator / first_denominator | |
b = second_numerator / second_denominator | |
print "%i.%s" % (result.pop(0), "".join(map(str, result))) |
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