Get YouTube vide direct links in Nodejs

yt-links.js

/**
* Call this in console and pass YT video url as first argument
* e.g.: node yt-links.js https://www.youtube.com/watch?v=axBuiB55CfA
* Direct links can be extracted at line 24
*/

const https = require('https');
var url = process.argv.slice(2)[0];
var url = new URL(url);
var searchParams = new URLSearchParams(url.search);

if(searchParams.has('v')){
    let vid = searchParams.get('v');
    let vid_info_url = `https://www.youtube.com/get_video_info?video_id=${vid}`;
    https.get(vid_info_url, (resp) => {
        let data;
        resp.on('data', (chunk) => {
            data += chunk;
        });
        resp.on('end', () => {
            let decoded = decodeURIComponent(data);
            let json = decoded.match(/({.+})/)[1]
            let links = JSON.parse(json).streamingData;
            console.log(links)
        });
        
    }).on("error", (err) => {
    console.log("Error: " + err.message);
    });
}

Same thing, but using node-fetch instead of https. This seems much faster.

const fetch = require('node-fetch');

var url = process.argv.slice(2)[0];
var url = new URL(url);
var searchParams = new URLSearchParams(url.search);

(async () => {
    if(searchParams.has('v')){
        let vid = searchParams.get('v');
        let vid_info_url = `https://www.youtube.com/get_video_info?video_id=${vid}`;
        let response = await fetch(vid_info_url);
        let text = await response.text();
        let decoded = decodeURIComponent(text);
        let json = decoded.match(/({.+})/)[1]
        let links = JSON.parse(json).streamingData;
        console.log(links)
    }
})()