Grab and parse iTunes App Store RSS feed and coiunt how many of the top grossing apps for a particular store are currently free

topgrossingfreeapps.py

#!/usr/bin/env python
 
# topgrossingfreeapps.py [country code]
# us, gb, ch, etc
 
# quick and dirty python script to grab the percentage
# of top grossing aps in a given app store which are
# currently free
 
import feedparser
import sys
 
cc = sys.argv[1] if len(sys.argv) > 1 else "us"
 
feed = feedparser.parse( "https://itunes.apple.com/"
			  + cc +
			  "/rss/topgrossingapplications/limit=400/xml" )
 
count = 0
free  = 0
 
for entry in feed['entries']:
 
	price = entry['im_price']['amount']
	count += 1
	 
	if price == "0.00000":
		free +=1
 
print "\nCountry Code : " + cc + \
	  "\nTotal : " + str(count) + \
	  "\nFree : " + str(free) + \
	  " ( " + str( (float(free)/count) * 100) + \
	  " % )\n"