ephf

#include <stdio.h>

int main(int argc, char** argv) {
    if(argc != 2) return fprintf(stderr, "usage: %s <file>\n", *argv), 1;

    FILE* file = fopen(argv[1], "r");
    if(!file) return perror("xxd"), 1;

    for(size_t o = 0; !feof(file); o += 16) {
        char s[16], i = 0;

ephf

#include <sys/socket.h>
#include <netinet/in.h>
#include <stdio.h>
#include <unistd.h>

int main() {
	int sfd = socket(PF_INET, SOCK_STREAM, 0);
	setsockopt(sfd, SOL_SOCKET, SO_REUSEADDR,
		&(int) { 1 }, sizeof(int));

ephf

The population grows as a result of two conditions:

1. The anual population growth is 1% of those already in the country.
2. 20,000 people immigrate each year.

If the population now is 50,000 people, what will the population be in 20 years?

The answer can be found using the recursive function:

$$f_0=50,000$$

ephf

#include <stdlib.h>
#include <string.h>
#include <assert.h>

#define vec_t(t) t*
#define vec() NULL

void vresv(size_t** v, size_t s) {
    if(!*v) return assert((*v = (size_t*) calloc(1, sizeof(size_t[2]) + s) + 2) - 2 && ((*v)[-2] = s));
    if((s += (*v)[-1]) <= (*v)[-2]) return;