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By this part we are going to assign nine (9) groups of project repositories including one (1) group of the central. All of them will be managed by an instance to represesent the pattern of true-prime-pairs via bilateral 9 sums.
The purpose of this instance is simulating the central behaviour on each pairs of human chromosomes. So the nine (9) groups would consist of three (3) containers + one (1) sub central + one (1) central + one (1) sub central + three (3) containers.
(7-1) + (12x9) = 6 + 108 = 114
Tabulate Prime by Power of 10
loop(10) = π(10)-π(1) = 4-0 = 4
loop(100) = π(100)-π(10)-1th = 25-4-2 = 19
loop(1000) = π(1000) - π(100) - 10th = 168-25-29 = 114
-----------------------+----+----+----+----+----+----+----+----+----+-----
True Prime Pairs Δ | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | Sum
=======================+====+====+====+====+====+====+====+====+====+=====
19 → π(10) | 2 | 3 | 5 | 7 | - | - | - | - | - | 4th 4 x Root
-----------------------+----+----+----+----+----+----+----+----+----+-----
17 → π(20) | 11 | 13 | 17 | 19 | - | - | - | - | - | 8th 4 x Twin
-----------------------+----+----+----+----+----+----+----+----+----+-----
13 → π(30) → 12 (Δ1) | 23 | 29 | - | - | - | - | - | - | - |10th
=======================+====+====+====+====+====+====+====+====+====+===== 1st Twin
11 → π(42) | 31 | 37 | 41 | - | - | - | - | - | - |13th
-----------------------+----+----+----+----+----+----+----+----+----+----- 2nd Twin
7 → π(60) → 19 (Δ12) | 43 | 47 | 53 | 59 | - | - | - | - | - |17th
-----------------------+----+----+----+----+----+----+----+----+----+----- 3rd Twin
5 → π(72) → 18 (Δ13) | 61 | 67 | 71 | - | - | - | - | - | - |20th
=======================+====+====+====+====+====+====+====+====+====+===== 4th Twin
3,2 → 18+13+12 → 43 | 73 | 79 | 83 | 89 | 97 | 101| 103| 107| 109|29th
=======================+====+====+====+====+====+====+====+====+====+=====
Δ Δ
12+13+(18+18)+13+12 ← 36th-Δ1=151-1=150=100+2x(13+12) ← 30th = 113 = 114-1
Let's sum them up so we get 9+1+9=19. Put them as one (1) unit so the whole objects will be 19 (sub objects)+1 (unit object)=20 objects. Thus this sum is what we called as bilateral 9 sums.
As a matter of the fact every schemes are contained in X/Y genes where the Y gene has has hardly any genes. When we do pair them as reproduction genes then we will come again to 3 containers + 1 sub central + 1 central + 1 sub central + 3 containers.
The X bears about 1,600 genes with varied functions. But the Y has hardly any genes; maybe 50, and only 27 of these are in the male-specific part of the Y.(The Conversation)
--------------------------------------------------------------
| |
=======================+====+====+====+====+====+====+====+====+====+===== |
19 → π(10) | 2 | 3 | 5 | 7 | - | - | - | - | - | 4th 4 x Root |
-----------------------+----+----+----+----+----+----+----+----+----+----- |
17 → π(20) | 11 | 13 | 17 | 19 | - | - | - | - | - | 8th 4 x Twin |
-----------------------+----+----+----+----+----+----+----+----+----+----- |
13 → π(30) → 12 (Δ1) | 23 | 29 | - | - | - | - | - | - | - |10th |
=======================+====+====+====+====+====+====+====+====+====+===== 1st Twin |
11 → π(42) | 31 | 37 | 41 | - | - | - | - | - | - |13th |
-----------------------+----+----+----+----+----+----+----+----+----+----- 2nd Twin |
7 → π(60) → 19 (Δ12) | 43 | 47 | 53 | 59 | - | - | - | - | - |17th |
-----------------------+----+----+----+----+----+----+----+----+----+----- 3rd Twin |
5 → π(72) → 18 (Δ13) | 61 | 67 | 71 | - | - | - | - | - | - |20th ---------------
=======================+====+====+====+====+====+====+====+====+====+===== 4th Twin
3,2 → 18+13+12 → 43 | 73 | 79 | 83 | 89 | 97 | 101| 103| 107| 109|29th
=======================+====+====+====+====+====+====+====+====+====+=====
When recombination is occur then the prime 13 is forced to → 12 where the impact (Δ1) goes to 18+13+12=43 on the last 7th row. This sequence is simulated by a flowchart having 12 arrows flowing on 10 (ten) shapes of prime 31 up to 71 (40 nodes).
This central doesn't exist phisically. However when we were going up by the form of nine (9) subs central + one (1) central + nine (9) subs central then we will get the human brain as the central.
Observing many literatures we finaly found that the pattern of this centralizing is done by a kind of neurotransmitter that works as a messenger by transmitting a signal. That is the way they are communicating each others.
A neurotransmitter is a signaling molecule secreted by a neuron to affect another cell across a synapse. The cell receiving the signal, any main body part or target cell, may be another neuron, but could also be a gland or muscle cell.. Wikipedia
However it seems that determining the pattern of this signalling either going up to the top of the brain or going down to the XX or XY genes even to the bottom of that little Y is staggeringly complex. Yet science points to a much more ambiguous reality.
Determination of biological sex is staggeringly complex, involving not only anatomy but an intricate choreography of genetic and chemical factors that unfolds over time. (ScientificAmerica)
Therefore here we would only take the fact that X bears about 1,600 genes with varied functions while the Y has 50, and only 27 of these are in the male-specific and how their relation with the 20 objects of bilateral 9 sum.
Let's start with the number of possible ancestors on the chromosome. A male individual has an X chromosome, which he received from his mother, and a Y chromosome, which he received from his father.
The number of ancestors at each level, Fn, is the number of female ancestors, which is Fn−1, plus the number of male ancestors, which is Fn−2. his is under the unrealistic assumption that the ancestors at each level are otherwise unrelated.
It has been noticed that the number of possible ancestors on the human X chromosome inheritance line at a given ancestral generation also follows the Fibonacci sequence.
This Fibonacci sequence is lied beautifully in the Pascal Triangle. Pascal's triangle has wide applications in Mathematics. We have seen that the most important applications relate to the binomial coefficients and combinatorics.
See that from 1 to 89 it consist of seven (7) steps which is originated by 1,15,35,28 before it goes bilateral. So that is why Y has 1+15+35-1=50, and only 28-1=27 of these are in the male-specific. This cycle is repeated through a palindromic sequence.
109th - 20th = 89th
As the matter of fact this 89 has a symmetrical relation with the 24th Prime Number & 24th Natural Number Not Divisible by 2, 3, or 5. This is the reason that we use this primes pattern on determining the centralizing process
So the 20 objects would pair another 19 and become 19 (sub objects) + 1 (unit object) + 19 (sub objects)=20+19=39 objects or it will be 40 when we put them as one (1) unit. This 40 will act as the interface between each of containers.
This scheme stands as the second section of bilateral sum. By the rest sections we will discuss the above seven (7) steps one by one so all together will compromise the nine (9) groups of project repositories as mentioned in the beginning.
All of these coincidences are already discussed in details by previous schemes as well the existence of gap by 33's that is parsing the 102.
Please note that we are not talking about the number of 19 which is the 8th prime. Here we are talking about 19th as sequence follow backward position of 19 as per the scheme below where the 19th prime which is 67 goes 15 from 66 to 51. From the 50 we gonna split the 15 by bilateral 9 sums resulting 2 times 15+9=24 which is 48. So the total of involved objects is 50+48=98.
π(1000) = π(Φ x 618) = 168 = 100 + 68 = (50x2) + (66+2) = 102 + 66
See the fact that last 15 is connected to 25 which is 24+Δ1 where as another 15 are also correlated with 24 in pairs. So here we would compound them within three (3) minor hexagon which has 24 each and one of them is carrying the (Δ1).
This cycle is repeated through a palindromic sequence.
| 1st (Form) | 2nd (Route) | 3rd (Channel) |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
150 | 151| 152| 153| 154| 155| 156| 157| 158| 159| 160| 161| 162| 163| 164| 165| 166| 167| 168|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+
Δ1 | 19 | - | 31 | 37 | - | - | - | - | - | - | - | - | - | - | 103| - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ2 | 20 | 26 | - | 38 | - | - | - | - | - | 74 | - | - | - | 98 | 104| - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ3 | 21 | 27 | - | 39 | - | - | - | - | - | 75 | - | - | - | 99 | 105| - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ4 | 22 | 28 | - | 40 | - | - | - | - | - | 76 | - | - | - |100 | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ5 | 23 | 29 | - | 41 | - | - | - | - | - | 77 | - | - | - |101 | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ6 | 24 | - | - | 42 | - | 54 | - | - | 72 | 78 | - | 90 | 96 | - | - | - | - | 114|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+
Δ7 | 25 | - | - | 43 | - | 55 | - | - | 73 | 79 | - | 91 | 97 | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ8 | - | - | - | 44 | - | 56 | - | - | - | 80 | - | 92 | - | - | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ9 | - | - | - | 45 | - | 57 | - | - | - | 81 | - | 93 | - | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ10 | - | - | - | 46 | 52 | 58 | - | 70 | - | 82 | 88 | 94 | - | - | - | - | 112| - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ11 | - | - | - | 47 | 53 | 59 | - | 71 | - | 83 | 89 | 95 | - | - | - | - | 113| - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+ T
Δ12 | - | - | - | 48 | - | 60 | 66 | - | - | 84 | - | - | - | - | - | 108| - | - | H
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+ E
Δ13 | - | - | - | 49 | - | 61 | 67 | - | - | 85 | - | - | - | - | - | 109| - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+ P
Δ14 | - | - | 32 | 50 | - | 62 | 68 | - | - | 86 | - | - | - | - | - | 110| - | - | O
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+ W
Δ15 | - | - | 33 | 51 | - | 63 | 69 | - | - | 87 | - | - | - | - | - | 111| - | - | E
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+ R
Δ16 | - | - | 34 | - | - | 64 | - | - | - | - | - | - | - | - | 106| - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+ O
Δ17 | - | - | 35 | - | - | 65 | - | - | - | - | - | - | - | - | 107| - | - | - | F
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ18 | - | 30 | 36 | - | - | - | - | - | - | - | - | - | - |102 | -| - | - | - | ∑=168
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16| 17| 18 | 19 | V
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+ S
| Δ Δ | Φ12 | Δ Δ |
113 150 ≜114-25 557 619 = 1+618
67 » 66, 78, 86 (OEIS A059756)
102 = 2+60+40 » (2,60.40)
96 is the smallest integer n for which π(n) = n/4.
π(96) = π(4x24) = 24
139 - (25-18-18-25) = (114-18) - 18 - 25 = (96-18) - 25 = 78 - 25 = 53
See that from 1 to 89 it consist of seven (7) steps which is originated by 1,15,35,28 before it goes bilateral.
The distribution of these scale has a bilateral symmetrical relationship along with the peculiarities of each numbers within the format (18,30,36) of prime hexagon so that it can represent the pattern of true-prime-pairs systemically.
(5 + 7 + 11 + 13) + (17 + 19) = 36 + 36 = 72
This 29 turns the finiteness position of 15 as the middle zero axis of the MEC30. So the next steps will start exactly with the same story as we have explained from the beginning.
MEC 30 claims to "illustrate and convey the connections between quantum mechanics, gravitation and mathematics in a new way" via the elementary level of numbers. It starts with a theory about the structure of light, which is then transferred to various areas of the natural sciences.
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---+-----+-----
1 | 1 | 18
---+-----+-----
2 | 19 | 29
---+-----+-----
3 | {30}|{43}
---+-----+-----
139 = 34th prime =(2x17)th prime
Scheme 13:9
===========
(1){1}-7: 7’
(1){8}-13: 6‘
(1)14-{19}: 6‘
------------- 6+6 -------
(2)20-24: 5’ |
(2)25-{29}: 5’ |
------------ 5+5 -------
(3)30-36: 7:{70,30,10²}|
------------ |
(4)37-48: 12• --- |
(5)49-59: 11° | |
--}30° 30• |
(6)60-78: 19° | |
(7)79-96: 18• --- |
-------------- |
(8)97-109: 13 |
(9)110-139:{30}=5x6 <--x-
--
{43}
$True Prime Pairs:
(5,7), (11,13), (17,19)
layer| i | f
-----+-----+---------
| 1 | 5
1 +-----+
| 2 | 7
-----+-----+--- } 36 » 6®
| 3 | 11
2 +-----+
| 4 | 13
-----+-----+---------
| 5 | 17
3 +-----+ } 36 » 6®
| 6 | 19
-----+-----+---------
The consciousness is awaken through to the 13th central sphere of Metatron’s Cube. The 13th sphere (the central circle) represents death and rebirth, endings and beginnings through all of Creation in all directions of time and space.
1155 / 5 = 286 - 55 = 200 + 31 = 231
layer| i | f
-----+-------+------
| 1,2:1 | (2,3)
1 +-------+
| 3:2 | (7)
-----+-------+------
| 4,6:3 | (10,11,12) <--- 231 (3x)
2 +-------+
|{7}:4 |({13})
-----+-------+------
| 8,9:5 | (14,{15}) <--- 231 (2x)
3 +-------+
| 10:6 | (19)
-----+-------+------
We study the limit shape of the generalized Young diagram when the tensor power N and the rank n of the algebra tend to infinity with N/n fixed. We derive an explicit formula for the limit shape and prove convergence to it in probability. We prove central limit theorem for global fluctuations around the limit shape (arXiv:2010.16383v4).
True Prime Pairs:
(5,7), (11,13), (17,19)
|------------------------- Skema-12 ------------------------|
|------------ 6¤ -------------|------------- 6¤ ------------|
|--------------------------- 192 ---------------------------|
|---- {23} ----|---- {49} ----|-- {29} -|--{30} --|-- 61 ---|
+----+----+----+----+----+----+----+----+----+----+----+----+
| 5 | 7 | 11 |{13}| 17 | 19 | 17 |{12}| 11 | 19 | 18 | 43 |
+----+----+----+----+----+----+----+----+----+----+----+----+
|--------- 5¤ ---------|---- {48} ----|----- {48} ---|{43}|
|--------- 5¤ ---------|------------ {96} -----------|{43}|
|--------- {53} ---------|-------------- {139} -------------|
|------- Skema-23 -------|------------- Skema-34 -----------|
Here we are talking about 19th as sequence follow backward position of 19 as per the scheme below where the 19th prime which is 67 goes 15 from 66 to 51.
The values p(1),,,,,,p(8)} of the partition function (1, 2, 3, 5, 7, 11, 15, and 22) can be determined by counting the Young diagrams for the partitions of the numbers from onr (1) to eight (8) (Wikipedia).
The Prime Spiral Sieve possesses remarkable structural and numeric symmetries. For starters, the intervals between the prime roots (and every subsequent row or rotation of the sieve) are perfectly balanced, with a period eight (8) difference sequence of: {6, 4, 2, 4, 2, 4, 6, 2} (Primesdemystified).
Tabulate Prime by Power of 10
loop(10) = π(10)-π(1) = 4-0 = 4
loop(100) = π(100)-π(10)-1th = 25-4-2 = 19
loop(1000) = π(1000) - π(100) - 10th = 168-25-29 = 114
-----------------------+----+----+----+----+----+----+----+----+----+-----
True Prime Pairs Δ | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | Sum
=======================+====+====+====+====+====+====+====+====+====+=====
19 → π(10) | 2 | 3 | 5 | 7 | - | - | - | - | - | 4th 4 x Root
-----------------------+----+----+----+----+----+----+----+----+----+-----
17 → π(20) | 11 | 13 | 17 | 19 | - | - | - | - | - | 8th 4 x Twin
-----------------------+----+----+----+----+----+----+----+----+----+-----
13 → π(30) → 12 (Δ1) | 23 | 29 | - | - | - | - | - | - | - |10th
=======================+====+====+====+====+====+====+====+====+====+===== 1st Twin
11 → π(42) | 31 | 37 | 41 | - | - | - | - | - | - |13th
-----------------------+----+----+----+----+----+----+----+----+----+----- 2nd Twin
7 → π(60) → 19 (Δ12) | 43 | 47 | 53 | 59 | - | - | - | - | - |17th
-----------------------+----+----+----+----+----+----+----+----+----+----- 3rd Twin
5 → π(72) → 18 (Δ13) | 61 | 67 | 71 | - | - | - | - | - | - |20th
=======================+====+====+====+====+====+====+====+====+====+===== 4th Twin
3,2 → 18+13+12 → 43 | 73 | 79 | 83 | 89 | 97 | 101| 103| 107| 109|29th
=======================+====+====+====+====+====+====+====+====+====+=====
Δ Δ
12+13+(18+18)+13+12 ← 36th-Δ1=151-1=150=100+2x(13+12) ← 30th = 113 = 114-1
Speaking of the Fibonacci number sequence, there is symmetry mirroring the above in the relationship between the terminating digits of Fibonacci numbers and their index numbers equating to members of the array populating the Prime Spiral Sieve.
These objects will then behave as a complex numbers that leads to trivial and complex roots of the 18th prime identity. Since the arithmetic mean of those primes yields 157 then the existence of 114 will remain to let this 18+19=37th prime number stands as the balanced prime.
286 - (231x5)/(11x7) = 286 - 1155/77 = 286 - 15 = 200 + 71 = 271
-----------------------+----+----+----+----+----+----+----+----+----+-----
True Prime Pairs Δ | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | Sum
=======================+====+====+====+====+====+====+====+====+====+=====
19 → π(10) | 2 | 3 | 5 | 7 | - | - | - | - | - | 4th 4 x Root
-----------------------+----+----+----+----+----+----+----+----+----+-----
17 → π(20) | 11 | 13 | 17 | 19 | - | - | - | - | - | 8th 4 x Twin
-----------------------+----+----+----+----+----+----+----+----+----+-----
13 → π(30) → 12 (Δ1) | 23 | 29 | - | - | - | - | - | - | - |10th ←------------ 10
=======================+====+====+====+====+====+====+====+====+====+===== 1st Twin
11 → π(42) | 31 | 37 | 41 | - | - | - | - | - | - |13th
-----------------------+----+----+----+----+----+----+----+----+----+----- 2nd Twin
7 → π(60) → 19 (Δ12) | 43 | 47 | 53 | 59 | - | - | - | - | - |17th
-----------------------+----+----+----+----+----+----+----+----+----+----- 3rd Twin
5 → π(72) → 18 (Δ13) | 61 | 67 | 71 | - | - | - | - | - | - |20th ←------------ 20
=======================+====+====+====+====+====+====+====+====+====+===== 4th Twin
3,2 → 18+13+12 → 43 | 73 | 79 | 83 | 89 | 97 | 101| 103| 107| 109|29th ------------→ 30
=======================+====+====+====+====+====+====+====+====+====+===== bilateral 9 sums
3,2 → 18+13+12 → 43 | 73 | 79 | 83 | 89 | 97 | 101| 103| 107| 109|29th ------------→ 30
=======================+====+====+====+====+====+====+====+====+====+===== 4th Twin
5 → π(72) → 18 (Δ13) | 61 | 67 | 71 | - | - | - | - | - | - |20th ←------------ 20
-----------------------+----+----+----+----+----+----+----+----+----+----- 3rd Twin
7 → π(60) → 19 (Δ12) | 43 | 47 | 53 | 59 | - | - | - | - | - |17th
| ----------- 5 -----------
| | |
↓ ↑ ↓
| 2' | 3' | 5' | 7' |
|--------------|-------------------|------------------------------|------------------------------|
| lexering = π(1000) | parsering = 1000/Φ |
|--------------|-------------------|------------------------------|------------------------------|
| mapping | feeding | syntaxing | grammaring |
+----+----+----+----+----+----+----+----+----+-----+----+----+----+----+----+-----+----+----+----+
| 30 | 31 | 32 | 33 | 34 | 35 | 36 | 37 | 38 | 39 | 40 | 41 | 42 | 43 | 44 | 45 | 46 | 47 | 48 |
+----+----+----+----+----+----+----+----+----+-----+----+----+----+----+----+-----+----+----+----+
| 2 | 60 | 40 | 1 | 30 | 30 | 5 | 1 | 30 | 200 | 8 | 40 | 50 | 1 | 30 | 200 | 8 | 10 | 40 |
+----+----+----+----+----+----+----+----+----+-----+----+----+----+----+----+-----+----+----+----+
↓ ↑ | |
| | | |
------------ 10 ------------- | |
↓ ↓ |
+----+----+----+
| 2 | 60 | 40 |
+----+----+----+
| | |
2+100 ◄-
-----------------------+----+----+----+----+----+----+----+----+----+----- |
True Prime Pairs Δ | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | Sum |
=======================+====+====+====+====+====+====+====+====+====+===== ↓
19 → π(10) | 2 | 3 | 5 | 7 | - | - | - | - | - | 4th ◄- 4 = π(10)
-----------------------+----+----+----+----+----+----+----+----+----+-----
It will be forced back to Δ19 making a cycle that bring back the 12 to → 13 of 9 collumns and replicate The Scheme 13:9 through (i=9,k=13)=9x3=27 with entry form of (100/50=2,60,40) as below:
| 1st (Form) | 2nd (Route) | 3rd (Channel) |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
150 | 151| 152| 153| 154| 155| 156| 157| 158| 159| 160| 161| 162| 163| 164| 165| 166| 167| 168|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+
Δ1 | 19 | - | 31 | 37 | - | - | - | - | - | - | - | - | - | - | 103| - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ2 | 20 | 26 | - | 38 | - | - | - | - | - | 74 | - | - | - | 98 | 104| - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ3 | 21 | 27 | - | 39 | - | - | - | - | - | 75 | - | - | - | 99 | 105| - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ4 | 22 | 28 | - | 40 | - | - | - | - | - | 76 | - | - | - |100 | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ5 | 23 | 29 | - | 41 | - | - | - | - | - | 77 | - | - | - |101 | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ6 | 24 | - | - | 42 | - | 54 | - | - | 72 | 78 | - | 90 | 96 | - | - | - | - | 114|
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+
Δ7 | 25 | - | - | 43 | - | 55 | - | - | 73 | 79 | - | 91 | 97 | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ8 | - | - | - | 44 | - | 56 | - | - | - | 80 | - | 92 | - | - | - | - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ9 | - | - | - | 45 | - | 57 | - | - | - | 81 | - | 93 | - | - | - | - | - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ10 | - | - | - | 46 | 52 | 58 | - | 70 | - | 82 | 88 | 94 | - | - | - | - | 112| - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ11 | - | - | - | 47 | 53 | 59 | - | 71 | - | 83 | 89 | 95 | - | - | - | - | 113| - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+ T
Δ12 | - | - | - | 48 | - | 60 | 66 | - | - | 84 | - | - | - | - | - | 108| - | - | H
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+ E
Δ13 | - | - | - | 49 | - | 61 | 67 | - | - | 85 | - | - | - | - | - | 109| - | - |
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+ P
Δ14 | - | - | 32 | 50 | - | 62 | 68 | - | - | 86 | - | - | - | - | - | 110| - | - | O
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+ W
Δ15 | - | - | 33 | 51 | - | 63 | 69 | - | - | 87 | - | - | - | - | - | 111| - | - | E
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+ R
Δ16 | - | - | 34 | - | - | 64 | - | - | - | - | - | - | - | - | 106| - | - | - |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+ O
Δ17 | - | - | 35 | - | - | 65 | - | - | - | - | - | - | - | - | 107| - | - | - | F
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ18 | - | 30 | 36 | - | - | - | - | - | - | - | - | - | - |102 | -| - | - | - | ∑=168
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16| 17| 18 | 19 | V
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+ S
| Δ Δ | Φ12 | Δ Δ |
113 150 ≜114-25 557 619 = 1+618By the prime hexagon this number 114 located on 6th row vs 19th column whereas 114th prime = 619 = 618+1. Since DNA Recombination is happen when two (2) chromosomes involve then they start the position as below:
| by the 1st chromosome | by the 2nd
+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
Δ18 | - | 30 | 36 | - | - | - | - | - | - | - | - | - | - |102 | -| - | - | - | 30 | 36 | - |
=====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+====+
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16| 17| 18 | 19 | 20 | 21 | 22 |
-----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
| Δ Δ | Φ12 | Δ Δ |
113 150 ≜114-25 557 619 = 1+618In the second opposing member, the position 19 in the second term gives a redundant value of the template 7 of 7 × 7 = 49. The opposite prime position 11 as a prime number is now forced to determine a new axis-symmetrical zero position.
The 77 is equal to the sum of the first eight (8) primes. The square of 77 is 5929, the concatenation of two primes, 59 and 29. The concatenation of all palindromes from one up to 77 is prime (Prime Curios! ).
Prime numbers that end with "77" occur more often than any other 2-digit ending among the first one million primes. The sum of the proper divisors of 77 equals 19 and the sum of primes up to 19 equals 77. Does this ever happen again?
Φ(10,2) = 10² + 2x(10th prime) + 10¹ = 100+29 + 29+10 = 129 + 39 = 168 = π(1000)
Φ = 2,10
Δ = 5,7,17
3': 13,18,25,42
2' » 13 to 77, Δ = 64
2' and 3' » 13 to 45, Δ = 32
2" + 5" = 7" = 77
2"=22, 3"=33, 2" + 3" = 5" = 55
13, 16, 18, 21, 23, 25, 28, 30, 32, 34,
36, 38, 40, 42,
45, 47, 49, 51, 53,
55, 57, 59, 61,
63, 65, 67, 69, 71, 73, 75, 77
The DNA base consists of 2 groups that are in pairs between Sugar and pospat with nucleotides. Let's weighting between the two. Each of these pospats consists of three (3) groups with five (5) oxygen bonds. This sugar and pospat forms a system that moves from 5' to 3' which is anti-parallel with movement at the other end which is 3' to 5'.
Each oxygen test has 2 electrons, so each group I give a weight of 2x5 or ten (10) so the total is 30. Sugar molecules are not groups so the weight is five (5) so that with a weight of 30 out of pospat the total is 35. Since there is a pair then the total is 70. Next we unite the format with nucleotides A,T,G,C paired 9+6 and 6+9 totaling 30 then the format of both is (70,30).
#8 |----------- 5® --------|------------ 7® --------------|
| 1 |---------------- 77 = 4² + 5² + 6² -------------|
-----+-----|-----+---+---+---+---+---+---+---+----+----+----+
repo| {1} | {2} | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 |{12}| 1,77
-----+-----|-----+---+---+---+---+---+---+---+----+----+----+
user| 7 | - | - | - | - | 7 | 8 | - | - | 8 | 8 | 3 |
-----+-----|-----+---+---+---+---+---+---+---+----+----+----+ 7,78
main| - | 9 | 7 | 9 | 6 | - | - | 8 | 5 | - | - | - |
-----+-----|-----+---+---+---+---+---+---+---+----+----+----+
Δ | Δ | Δ | Δ
Φ17|Φ29 | 96-99| 100 - 123 ({24})
|--- A,T,G,C ---| | └── 100 - 103 (4x) » 100
Δ 2x2 = 4x |------- 2x3 = 6x -------| └── 104 - 109 (6x) » 30
{98} | └── 110 - 123 (14x)» 70
Here we unite with the whole bond which of course is the number of the two, namely 100, then the sum of the DNA bases, namely Pospat, Sugar and Nukeotides is 200 with the format (70,30,100).
(2x5x7,2x3x5,2²x5²) = (14x5,15x2,20x5) = (70,30,100)
114 - 102 = 12 » {1} & {2}
This recombination scheme shall be made available on each of instance that composing 7 blocks. Since these blocks are spread in to 29 flats that bring a total of 77 rooms then the total objects per instance would become 114.
Φ(13:9) = Φ(29th prime) = Φ(109) = (2+69) + 68 = 71 + 68 = 139
-------------------+-----+-----+ ---
786 ‹------- 20:13| 90 | 90 (38) ‹-------------- ¤ |
| +-----+-----+ |
| 618 ‹- 21,22:14| 8 | 40 | 48 (40,41) ‹---------------------- 17¨ class
| | +-----+-----+-----+-----+-----+ | |
| | 594 ‹- 23:15| 8 | 40 | 70 | 60 | 100 | 278 (42) «-- |{6'®} |
| | | +-----+-----+-----+-----+-----+ | | ---
--|--|-»24,27:16| 8 | 40 | 48 (43,44,45,46) ------------|---- |
| | +-----+-----+ | |
--|---› 28:17| 100 | {100} (50) ------------------------» 19¨ object
168 | +-----+ |
| 102 -› 29:18| 50 | 50(68) ---------> Δ18 |
----------------------+-----+ ---
In this analogy, the basic question is: is the puzzle really as hard as we think, or are we missing something? This issue was first raised by the baffling Austrian-American mathematician Kurt Gödel. It was formulated as P ≠ NP by Stephen Cook in 1971.
P is a polynomial and NP is a non-deterministic polynomial. In informal terms, it asks whether every problem whose solution can be quickly verified can also be quickly solved. In simpler terms, P means a problem that is easily solved by a computer, and NP means a problem that a computer is not easy to solve but is easy to check.
(5, 2, 1, 0)
(7, 3, 1, 0)
(11, 4, 1, 0)
(13, 5, 1, 0)
(17, 0, 1, 1)
(19, 1, 1, 1)
(23, 2, 1, 1)
(29, 2, -1, 1)
(31, 1, -1, 1)
(37, 1, 1, 1)
(41, 2, 1, 1)
(43, 3, 1, 1)
(47, 4, 1, 1)
(53, 4, -1, 1)
(59, 4, 1, 1)
(61, 5, 1, 1)
(67, 5, -1, 1)
(71, 4, -1, 1)
(73, 3, -1, 1)
(79, 3, 1, 1)
(83, 4, 1, 1)
(89, 4, -1, 1)
(97, 3, -1, 1)
(101, 2, -1, 1)
(103, 1, -1, 1)
(107, 0, -1, 1)
(109, 5, -1, 0)
(113, 4, -1, 0)
(127, 3, -1, 0)
(131, 2, -1, 0)
(137, 2, 1, 0)
(139, 3, 1, 0)
(149, 4, 1, 0)
(151, 5, 1, 0)
(157, 5, -1, 0)
(163, 5, 1, 0)
(167, 0, 1, 1)
(173, 0, -1, 1)
(179, 0, 1, 1)
(181, 1, 1, 1)
(191, 2, 1, 1)
(193, 3, 1, 1)
(197, 4, 1, 1)
(199, 5, 1, 1)
(211, 5, -1, 1)
(223, 5, 1, 1)
(227, 0, 1, 2)
(229, 1, 1, 2)
(233, 2, 1, 2)
(239, 2, -1, 2)
(241, 1, -1, 2)
(251, 0, -1, 2)
(257, 0, 1, 2)
(263, 0, -1, 2)
(269, 0, 1, 2)
(271, 1, 1, 2)
(277, 1, -1, 2)
(281, 0, -1, 2)
(283, 5, -1, 1)
(293, 4, -1, 1)
(307, 3, -1, 1)
(311, 2, -1, 1)
(313, 1, -1, 1)
(317, 0, -1, 1)
(331, 5, -1, 0)
(337, 5, 1, 0)
(347, 0, 1, 1)
(349, 1, 1, 1)
(353, 2, 1, 1)
(359, 2, -1, 1)
(367, 1, -1, 1)
(373, 1, 1, 1)
(379, 1, -1, 1)
(383, 0, -1, 1)
(389, 0, 1, 1)
(397, 1, 1, 1)
(401, 2, 1, 1)
(409, 3, 1, 1)
(419, 4, 1, 1)
(421, 5, 1, 1)
(431, 0, 1, 2)
(433, 1, 1, 2)
(439, 1, -1, 2)
(443, 0, -1, 2)
(449, 0, 1, 2)
(457, 1, 1, 2)
(461, 2, 1, 2)
(463, 3, 1, 2)
(467, 4, 1, 2)
(479, 4, -1, 2)
(487, 3, -1, 2)
(491, 2, -1, 2)
(499, 1, -1, 2)
(503, 0, -1, 2)
(509, 0, 1, 2)
(521, 0, -1, 2)
(523, 5, -1, 1)
(541, 5, 1, 1)
(547, 5, -1, 1)
(557, 4, -1, 1)
(563, 4, 1, 1)
(569, 4, -1, 1)
(571, 3, -1, 1)
(577, 3, 1, 1)
(587, 4, 1, 1)
(593, 4, -1, 1)
(599, 4, 1, 1)
(601, 5, 1, 1)
(607, 5, -1, 1)
(613, 5, 1, 1)
(617, 0, 1, 2)
(619, 1, 1, 2)
(631, 1, -1, 2)
(641, 0, -1, 2)
(643, 5, -1, 1)
(647, 4, -1, 1)
(653, 4, 1, 1)
(659, 4, -1, 1)
(661, 3, -1, 1)
(673, 3, 1, 1)
(677, 4, 1, 1)
(683, 4, -1, 1)
(691, 3, -1, 1)
(701, 2, -1, 1)
(709, 1, -1, 1)
(719, 0, -1, 1)
(727, 5, -1, 0)
(733, 5, 1, 0)
(739, 5, -1, 0)
(743, 4, -1, 0)
(751, 3, -1, 0)
(757, 3, 1, 0)
(761, 4, 1, 0)
(769, 5, 1, 0)
(773, 0, 1, 1)
(787, 1, 1, 1)
(797, 2, 1, 1)
(809, 2, -1, 1)
(811, 1, -1, 1)
(821, 0, -1, 1)
(823, 5, -1, 0)
(827, 4, -1, 0)
(829, 3, -1, 0)
(839, 2, -1, 0)
(853, 1, -1, 0)
(857, 0, -1, 0)
(859, 5, -1, -1)
(863, 4, -1, -1)
(877, 3, -1, -1)
(881, 2, -1, -1)
(883, 1, -1, -1)
(887, 0, -1, -1)
(907, 5, -1, -2)
(911, 4, -1, -2)
(919, 3, -1, -2)
(929, 2, -1, -2)
(937, 1, -1, -2)
(941, 0, -1, -2)
(947, 0, 1, -2)
(953, 0, -1, -2)
(967, 5, -1, -3)
(971, 4, -1, -3)
(977, 4, 1, -3)
(983, 4, -1, -3)
(991, 3, -1, -3)
(997, 3, 1, -3)
139 = 34th prime =(2x17)th prime
Scheme 13:9
===========
(1){1}-7: 7’
(1){8}-13: 6‘
(1)14-{19}: 6‘
------------- 6+6 -------
(2)20-24: 5’ |
(2)25-{29}: 5’ |
------------ 5+5 -------
(3)30-36: 7:{70,30,10²}|
------------ |
(4)37-48: 12• --- |
(5)49-59: 11° | |
--}30° 30• |
(6)60-78: 19° | |
(7)79-96: 18• --- |
-------------- |
(8)97-109: 13 |
(9)110-139:{30}=5x6 <--x-- (129/17-139/27)
--
{43}
M: 6® = (2,{3}), ({29,30,31,32}) --> 2,89+29,3 = 289+329 = 618 (main)
F: 6'® = (40,41), (43,44,45,46) --> 30+30+10+10+10+10 = 60+40 (user)
C1: 10°® = 3*®+3*®+4® = (7,13,19),(20,27,36),({38,42,50,68}) --> 200 (main)
C2: 7® = 5®+2® = 1®+4*®+2*® = 1®+6*® = 10,(11,12,14,15,26,28) --> 168 (user)
π (Φ (329 + 289)) = π (Φ x 618) = π (1000) = 168
1st layer:
It has a total of 1000 numbers
Total primes = π(1000) = 168 primes
2nd layer:
It will start by π(168)+1 as the 40th prime
It has 100x100 numbers or π(π(10000)) = 201 primes
Total cum primes = 168 + (201-40) = 168+161 = 329 primes
3rd layer:
Behave the same as 2nd layer which has a total of 329 primes
The primes will start by π(π(π(1000th prime)))+1 as the 40th prime
This 1000 primes will become 1000 numbers by 1st layer of the next level
Total of all primes = 329 + (329-40) = 329+289 = 618 = 619-1 = 619 primes - Δ1
# pinned repos
# https://dev.to/thomasaudo/get-started-with-github-grapql-api--1g8b
echo -e "\n$hr\nPINNED REPOSITORIES\n$hr"
AUTH="Authorization: bearer $JEKYLL_GITHUB_TOKEN"
curl -L -X POST "${GITHUB_GRAPHQL_URL}" -H "$AUTH" \
--data-raw '{"query":"{\n user(login: \"'${GITHUB_REPOSITORY_OWNER}'\") \
{\n pinnedItems(first: 6, types: REPOSITORY) {\n nodes {\n ... on Repository \
{\n name\n }\n }\n }\n }\n}"'
================================================================================
PINNED REPOSITORIES
================================================================================
% Total % Received % Xferd Average Speed Time Time Time Current
Dload Upload Total Spent Left Speed
0 0 0 0 0 0 0 0 --:--:-- --:--:-- --:--:-- 0
100 292 100 150 100 142 1171 1109 --:--:-- --:--:-- --:--:-- 2281
{"data":{"user":{"pinnedItems":{"nodes":[{"name":"maps"},{"name":"feed"},
{"name":"lexer"},{"name":"parser"},{"name":"syntax"},{"name":"grammar"}]}}}}
GitHub graphQL API multiple queries on organizations &
curl -L -X POST "${GITHUB_GRAPHQL_URL}" -H "$AUTH" \
--data-raw '{"query":"{\n organization(login: \"'${GITHUB_REPOSITORY_OWNER}'\") \
{\n pinnedItems(first: 6, types: REPOSITORY) {\n nodes {\n ... on Repository \
{\n name\n }\n }\n }\n }\n}"'
================================================================================
PINNED REPOSITORIES
================================================================================
% Total % Received % Xferd Average Speed Time Time Time Current
Dload Upload Total Spent Left Speed
0 0 0 0 0 0 0 0 --:--:-- --:--:-- --:--:-- 0
100 292 100 150 100 142 1171 1109 --:--:-- --:--:-- --:--:-- 2281
{"data":{"organization":{"pinnedItems":{"nodes":[{"name":"classifier"},
{"name":"domJSON"},{"name":"openoffice"},{"name":"landing-page-theme"},
{"name":"asciidoc"},{"name":"recommendations-ai"}]}}}}
1 instance + 7 blocks + 29 flats + 77 rooms = 114 objects
True Prime Pairs:
(5,7), (11,13), (17,19)
-----+-----+-----+-----+-----+ -----------------------------------------------
{786}| 1,2 | 2 | 2,3 | 3,4 | {19} |
-----+-----+-----+-----+-----+ |
{86}| 4 | 4,5 | 5,6 |{6,7}| 17 Base Zone
+-----+-----+-----+-----+ |
{78}|{7,8}| 8,9 | 12 (M dan F) ----> Δ |
+-----+-----+-----+ -----------
{67}| 9,11|11,12|12,14| 11 <----------- Mid Zone |
----+-----+-----+-----+-----+ |
{6}|15,16|17,18|18,20|21,22| 19 Mirror Zone
+-----+-----+-----+-----+ |
{8}|23,25|25,27|27,29| 18 |
+-----+-----+-----+-----+-----+-----+-----+-----+-------+ -----------
{7}|29,33|33,36|36,39|39,41|41,45|46,51|51,57|58,66|{67,77}| 43 (C1 dan C2)<---Δ
-----+-----+-----+-----+-----+-----+-----+-----+-----+-------+ -----------
| 1 2 3 | 4 5 6 | 7 8 9 |
|------ 29' ------|--------------- 139' ----------------|
|------ 102¨ -----|--------------- 66¨ ----------------|
114 = 102 + 66 - 29 - 25 = 6 + (6x6) + 6 x (6+6) = 6 x (6+6) + 6 + (6x6) = 25 + 89
6 x 114 - 30 - 30 - 5 = 619 = 6 x 19 = 114th prime
π(1000) + 1000/Φ = 168 + 618 = (7x71) + (17x17) = 786
To make it easier to develop a program following a model, we divide the object by placing it into a smaller objects. We do this division by adopting the OOP (Object Oriented Programming) which is an object-oriented programming method.
139 + 286 + 114 + 247 + 157 + 786 = 786 + 157 + 786 = 1729 = 7 x 13 x 19
168 + 329 + 289 = 168 + 618 = 786
Using this method then out of bilateray way of 19 vs 18 we could get in to Scheme-33. By a decomposition the subject is divided into six (6) parts, each part is further regrouped in to 19 sub-parts so finaly we got π(1000/Φ)=π(618)=114 objects.
d(43,71,114) = d(7,8,6) » 786
By defining the pattern on each individual numbers against homogeneous sorting out of these 114 objects then we finally come to a scale called MEC30 which is based on the beauty of Euler's identity.
Mathematics writer Constance Reid has opined that Euler's identity is the most famous formula in all mathematics. And Benjamin Peirce, a 19th-century American philosopher, mathematician, and professor at Harvard University, after proving Euler's identity during a lecture, stated that the identity "is absolutely paradoxical; we cannot understand it, and we don't know what it means, but we have proved it, and therefore we know it must be the truth" (Wikipedia)
Although this may seem very fast, a much more sophisticated method, combined with a very powerful computer, is necessary to find very large primes. Despite there are many studies and papers it is still an important open problem today.
The Millennium Prize Problems are seven problems in mathematics that were stated by the Clay Mathematics Institute in 2000. Currently, six of the problems remain unsolved (Wikipedia).
In the next section we will discuss about algorithms in applications and their relation to the distribution of prime numbers.
Based on the homogeneous sorting of objects against these 114 repositories we will get the number 57 which is distributed over the pair of objects whose difference is twenty-nine (29). So everything will happen to repeat in this 29.
(114/2)! = 57! = 1653 » 1653 / 57 = 29
--------+
| ⅓
+--- } ⅔
Case A | ⅓
+---------
| ⅓ |
-----------------+ Φ = ⅔
| ⅓ |
+---------
Case B | ⅓
+--- } ⅔
| ⅓
---------
By this objects pairing there would exist a zone segregation numbers (28.29) on each of the pairs. Since 10 stands as the central zone then it would be a tensor between 29-10=19 and 28-10=18.
9 + 19 + 29 = 28 + 29 = (10+18) + (10+19) = 57
P7:(142857)
# | A | B | ∑
------+------+------+-----
{1} | | |
------+ | |
... | 28 | 29 | 57
------+ | |
{57} | | |
------+------+------+-----
58 | | |
------+ | |
... | 29 | 28 | 57
------+ | |
114 | | |
------+------+------+-----
| 57 | 57 | 114
This zone is cenralized by the 20 objects while the tensor of 19 vs 18 is polarizing the 2x11x13=286 objects out of the pairing of 11 and 13 within the True Prime Pairs and finally be composed by 20/10 = 2 numbers of 285 and 286 that having a total of 571.
Φ((13,12),(12,18)) = Φ(13,((19,18),(18,43)) = Φ(13,37,61) = Φ(6,12,18)th prime
---+-----+-----+-----+-----+
1 |{19} | 1 |{20} | 21 |-----------------------
---+-----+-----+-----+-----+ |
2 | 18 | 21 | 39 | 60 |----------------- |
---+-----+-----+-----+-----+ | |
3 | 63 | 40 | 103 |{143}|----------- | |
---+-----+-----+-----+-----+ | | |
4 | 37 | 104 | 141 | 245 |----- | | |
---+-----+-----+-----+-----+ | | | |
5 | 10 | 142 | 152 | 294 |-{11}|{13} |{12} |{12} |{18}
---+-----+-----+-----+-----+ | | | |
6 | 24 | 153 |{177}| 332 |----- | | |
---+-----+-----+-----+-----+ | | |
7 | 75 | 178 | 253 | 431 |----------- | |
---+-----+-----+-----+-----+ | |
8 | 30 | 254 | 284 | 538 |----------------- |
---+-----+-----+-----+-----+ |
9 | 1 | 285 | 286 |{571}|-----------------------
===+=====+=====+=====+=====+
45 |{277}|
---+-----+
However by the prime numbers this behaviour is not happened by the number of 57 but on the 157 as the 19+18=37th prime. So on the pairing of 57 to 114 above then one of them is forced to behave as 157-57=100 which is exactly the square of 10.
157 is the 37th prime number, a balanced prime, because the arithmetic mean of those primes yields 157. The next prime is 163 and the previous prime is 151, with which 157 forms a prime triplet. (Wikipedia)
By this square correlation between natural and prime numbers then the 571 would be separated by the 100 to 500 and 71 and finally by the form of (2,10) the 500 goes to 50 while 71 would be polarized to form 71x2=142 and 177 as shown on the table.
(10/2)π = 157 ⇄ (10^2)¹ + 11x7 = 177
That is why DNA is twisted and spinning in the scope of three (3) directions in three (3) dimensions which in its entirety resembles the shape of a trifoil. For XX genes this lead to 1600 objects but for XY genes there are different story.
When a 3 × 3 × 3 cube is made of 27 unit cubes, 26 of them are viewable as the exterior layer. (Wikipedia)
From this arrangement we get the sum of all vectors with the sequence at number 247 where via the number one (1) makes 10 connected with 13 and 14 to the number twenty-seven (27).
Φ(11,13) = (114 - 10²) + 13 = 27 = 9 x 3 = 3 x 3 x 3 = 3 ^ 3
----------+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
seq | {1}| 2 | 3 | 4 | 5 | {6}| {7}| 8 | 9 | 10 | 11 | 12 | 13 | 14 |
----------+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
num | {3}| {4}| 3 | 4 | 5 | 2 | 3 | 2 | 2 | 1 | 2 | 5 | 1 | 1 |{38}
----------+----+----+----+----+----+----+----+----+----+----+----+----+----+----+---- } 285
seq x num | 3 | 8 | 9 | 16 | 25 |{12}|{21}| 16 | 18 | 10 | 22 | 60 |{13}|{14}|{247}
----------+----+----+----+----+----+----+----+----+----+----+----+----+----+----+
|-- 11 ---| |-- 33 ---| |-- {27}--|
Since there are no twin primes between 26² and 28² so they would goes to the rest object of 27. As you can see the formation of 69 objects from the number 29 ends in a 6 x 9 matrix centrally.
6 + (6x6) + 6 x (6+6) = 6 x (6+6) + 6 + (6x6) = 72 + 42 = 114
The Prime Recycling ζ(s):
(2,3), (29,89), (36,68), (72,42), (100,50), (2,3), (29,89), ...**infinity**
----------------------+-----+-----+-----+ ---
7 --------- 1,2:1| 1 | 30 | 40 | 71 (2,3) ‹-------------@---- |
| +-----+-----+-----+-----+ | |
| 8 ‹------ 3:2| 1 | 30 | 40 | 90 | 161 (7) ‹--- | 5¨ encapsulation
| | +-----+-----+-----+-----+ | | |
| | 6 ‹-- 4,6:3| 1 | 30 | 200 | 231 (10,11,12) ‹--|--- | |
| | | +-----+-----+-----+-----+ | | | ---
--|--|-----» 7:4| 1 | 30 | 40 | 200 | 271 (13) --› | {5®} | |
| | +-----+-----+-----+-----+ | | |
--|---› 8,9:5| 1 | 30 | 200 | 231 (14,15) ---------› | 7¨ abstraction
289 | +-----+-----+-----+-----+-----+ | |
| ----› 10:6| 20 | 5 | 10 | 70 | 90 | 195 (19) --› Φ | {6®} |
--------------------+-----+-----+-----+-----+-----+ | ---
67 --------› 11:7| 5 | 9 | 14 (20) --------› ¤ | |
| +-----+-----+-----+ | |
| 78 ‹----- 12:8| 9 | 60 | 40 | 109 (26) «------------ | 11¨ polymorphism
| | +-----+-----+-----+ | | |
| | 86‹--- 13:9| 9 | 60 | 69 (27) «-- Δ19 (Rep Fork) | {2®} | |
| | | +-----+-----+-----+ | | ---
| | ---› 14:10| 9 | 60 | 40 | 109 (28) ------------- | |
| | +-----+-----+-----+ | |
| ---› 15,18:11| 1 | 30 | 40 | 71 (29,30,31,32) ---------- 13¨ inheritance
329 | +-----+-----+-----+ |
| ‹--------- 19:12| 10 | 60 | {70} (36) ‹--------------------- Φ |
-------------------+-----+-----+ ---
786 ‹------- 20:13| 90 | 90 (38) ‹-------------- ¤ |
| +-----+-----+ |
| 618 ‹- 21,22:14| 8 | 40 | 48 (40,41) ‹---------------------- 17¨ class
| | +-----+-----+-----+-----+-----+ | |
| | 594 ‹- 23:15| 8 | 40 | 70 | 60 | 100 | 278 (42) «-- |{6'®} |
| | | +-----+-----+-----+-----+-----+ | | ---
--|--|-»24,27:16| 8 | 40 | 48 (43,44,45,46) ------------|---- |
| | +-----+-----+ | |
--|---› 28:17| 100 | {100} (50) ------------------------» 19¨ object
168 | +-----+ |
| 102 -› 29:18| 50 | 50(68) ---------> Δ18 |
----------------------+-----+ ---
From this number 27, we can start the process by taking the initial vector of 69 as the number of objects that is originated from 10th prime = 29 so the 29th=109 objects out of the 10 objects of the central zone is actually decoded from 110 objects of 18th prime. Therefore the polarizing of 19 vs 18 by the prime hexagon should also involve 3 times 100+3=309 objects.
This pattern is raised up per six (6) cycles on the 18+1=19, 42+1=43 and 72-1=71. Since the members are limited to the sum of 43+71=114 so here the bilateral way of 19 that originated by the (Δ1) is clearly the one that controls the scheme.
6 x (1 + 6 + (6 + 6)) = 6 + 36 + 72 = 42 + 72 = 43 + 71 = 114
This polarity is happened per six (6) cycles by the polar of six (6) to one (1) and six (6) to seven (7) by which we finally found if this behaviour is cascaded bilaterally within the correlation between 61 as the 18th prime and 67 as the 19th prime.
1/7 = 0,142857142857142857142857.. cycling six (6) numbers of (1,4,2,8,5,7) infinity
This curve is a polar plot of the first 20 non-trivial Riemann zeta function zeros including Gram points along the critical line ζ(1/2+t) for real values of t running from 0 to 50. The consecutive zeros have 50 red plot points between each with zeros identified by magenta concentric rings (scaled to show the relative distance between their values of t).
20x10+ ½(16×6) + ¼(12×18) + ⅛(16×16) = 200 + 48 + 32 + 6 = 286
See on the left side contains of odd numbers less and equal to 19 while the right is the even number less and equal to 18. By the left side only 9 and 15 that are not primes. Consider these two (2) numbers are laid side by side as part of Fibonacci sequence on the Pascal Triangle. Thus the above curve is actually represesenting the pattern of true-prime-pairs via bilateral 9 sums.
Meanwhile the sum of 28 and 35, which is 63, has a digital root of 6+3 = 9 and is landed precisely on the 15's cell of the prime hexagon. So the interaction with the seven (7) objects is made through the object of 36 which has the same digital root of 9.
36® - 9® (1,2,10,47,66,73,86,102,107) - 6°(diagram) - 12® (pinned) = 36® - 27® = 9®
As you may see the correlation between each items could involve a complex geometry either by area or volume object that may lead to their tensor and gap. So we decided to assign these behaviours one by one in to a separate group of repositories.
{10,11,12,14,15} & {26,28} = {5®} & {2®} = {7®} = {30,31,32,33,34,35,36}
As conclusion to this presentation is that the structure of those prime numbers is not happened by a coincidence. It might hard to believe if they were specifically designed to become the base algorithm on generating the human chromosomes from DNA.
By the next parts this will go much more details. Such as the generation of the said DNA from its particular atoms and molecules from the nature of universe which may bring another conclusion if it was initiated by a gap.
₠Quantum Project
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