Created
April 13, 2013 16:57
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Example 6 at Library.
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#include <iostream> | |
using namespace std; | |
char * myFunction(const char * str) | |
{ | |
//Declare the fixed size array of 32 ize. | |
char fixedSizeArray[32]; | |
//Copy str into it. | |
strcpy(fixedSizeArray, str); | |
//Return it. | |
return fixedSizeArray; | |
//Althout it does not result in a compiler error, it fails because it's returning the address of temporary data (myFixedArray) | |
} | |
char * myGoodFunction(const char * str) | |
{ | |
//In order to make it work: | |
//Declare new pointer, and initialize it to a new character array of 32 size. | |
char * dynamicArray = new char[32]; | |
//Copy str into it. | |
strcpy(dynamicArray, str); | |
//Return it. | |
return dynamicArray; | |
//Note that if we do not keep track of the returned data, it results in a memory leak (since a new object was dynamically created.) | |
} | |
void main() | |
{ | |
//Print result of myFunction with "Teeeeesting!" as the argument. | |
cout << myFunction("Teeeeesting!") << endl; | |
//Get result of myGoodFunction with "Teeeeesting!" as the argument. | |
//Needs to be done to avoid a memory leak. | |
char * result = myGoodFunction("Teeeeesting!"); | |
//Print out result. | |
cout << result << endl; | |
//Delete result. For deleting an array, delete requires the empty []. | |
//Otherwise delete things it's just getting a pointer to a single item, rather than array. | |
//So if [] was left off, it would assume that it was only getting a pointer to the first character in result. | |
delete [] result; | |
} |
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