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August 29, 2015 14:01
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I expect the following code to yield a random permutation of {1,2,3,4}. However, it always outputs 1,2,3,4 in order. What's wrong with it?
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| (1 to 4).foreach(i => { | |
| val f = scala.actors.Futures.future { | |
| Thread.sleep(scala.util.Random.nextInt(10) * 500) | |
| println(i) | |
| } | |
| f() | |
| }) |
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