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PatternDistance
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# DB is dictionary with tuple of pattern as key and support as value | |
# P1 and P2 are lists or arrays of the keys to compare | |
# this will only work if one of P1 and P2 is a subset of the other | |
def pattern_distance(P1, P2, db): | |
P1_support = db[tuple(P1)] | |
P2_support = db[tuple(P2)] | |
# if P1 is a subset of P2 then we just use their supports | |
if set(P1).issubset(set(P2)): | |
return 1 - (P2_support / P1_support) | |
# else if P2 is a subset of P1 we flip it around | |
elif set(P2).issubset(set(P1)): | |
return 1 - (P1_support / P2_support) | |
else: | |
return 0 | |
# takes two patterns and a complete DB and returns the | |
# pattern distance, calculating the supports from the db | |
def pattern_distance2(P1, P2, db): | |
# initialize our counts | |
P1orP2_count = 0 | |
P1andP2_count = 0 | |
# convert P1 and P2 to sets so we can do subset testing | |
P1 = set(P1) | |
P2 = set(P2) | |
# loop through the DB getting the support for (P1 and P2) and (P1 or P2) | |
for transaction in db: | |
trans_set = set(transaction) | |
# if both P1 and P2 are in the transaction then we increment both counts | |
if P1.issubset(trans_set) and P2.issubset(trans_set): | |
P1andP2_count += 1 | |
P1orP2_count += 1 | |
# else if only one of them is we increment the intersect count | |
elif P1.issubset(trans_set) or P2.issubset(trans_set): | |
P1orP2_count += 1 | |
return 1 - (P1andP2_count / P1orP2_count) |
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