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Spring Custom UserDetails

How to use Custom DAO class in Spring Security

Source

  • Objective 1 : Use Custom DAO classes in Spring Security Spring Security provides mechanism by which we can specify database queries in spring security xml file , but sometimes we want to use our own custom dao classes which are already built.
  • Objective 2 : Forward the request to different home pages based on the authorized role

First , to use your custom dao class , we have to create a bean which implements org.springframework.security.userdetails.UserDetailsService interface. Override the loadUserByUserName method of this interface. We have to create org.springframework.security.userdetails.User from our custom dao object.

package com.security;

import org.springframework.security.GrantedAuthority;
import org.springframework.security.GrantedAuthorityImpl;
import org.springframework.security.userdetails.User;
import org.springframework.security.userdetails.UserDetails;
import org.springframework.security.userdetails.UserDetailsService;
import org.springframework.security.userdetails.UsernameNotFoundException;
import com.dal.interfaces.UserDAO;
import com.exceptions.DAOException;

/**
 * This class is used by spring controller to authenticate and authorize user
 * modified this class to user our Database and defined user roles
 * 
 * @author abhishek.somani
 */
public class UserDetailServiceImpl implements UserDetailsService {

    private UserDAO userdao;

    public void setUserdao(UserDAO userdao) {
        this.userdao = userdao;
    }

    // this class is used by spring controller to authenticate and authorize user
    @Override
    public UserDetails loadUserByUsername(String userId)
                                          throws UsernameNotFoundException {
        com.model.User u;
        try {
            u = userdao.get(userId);
            if (u == null)
                throw new UsernameNotFoundException("user name not found");

        } catch (DAOException e) {
            throw new UsernameNotFoundException("database error ");
        }
        return buildUserFromUserEntity(u);
    }

    private User buildUserFromUserEntity(com.model.User userEntity) {
        // convert model user to spring security user
        String username               = userEntity.getUserId();
        String password               = userEntity.getPassword();
        boolean enabled               = true;
        boolean accountNonExpired     = true;
        boolean credentialsNonExpired = true;
        boolean accountNonLocked      = true;
        GrantedAuthority[] authorities = new GrantedAuthorityImpl[1];
        authorities[0] = new GrantedAuthorityImpl(userEntity.getRole());

        User springUser = new User(username, 
                                   password, 
                                   enabled,
                                   accountNonExpired, 
                                   credentialsNonExpired, 
                                   accountNonLocked,
                                   authorities);
        return springUser;
    }
}

In Spring-security.xml we have to give reference of this bean in user-service-ref in authentication-provider tag.

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
 xmlns:security="http://www.springframework.org/schema/security"
 xmlns:context="http://www.springframework.org/schema/context"
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
 xsi:schemaLocation="http://www.springframework.org/schema/beans
                     http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
                     http://www.springframework.org/schema/security
                     http://www.springframework.org/schema/security/spring-security-2.0.1.xsd
                     http://www.springframework.org/schema/context/spring-context-2.5.xsd">

<!-- this is security configuration file which maps urls according to user roles authorization -->

    <security:http auto-config="true">

        <security:logout logout-success-url="/login" 
                         invalidate-session="true" 
                         logout-url="/logout" />

        <security:intercept-url pattern="/login.jsp" filters="none" />
        <security:intercept-url pattern="/login"     filters="none" />
        <security:intercept-url pattern="/logout"    filters="none" />
        <security:intercept-url pattern="/Test"      access="ROLE_ADMIN" />
        <security:intercept-url pattern="/home"      access="ROLE_ADMIN,ROLE_USER"/>
        <security:intercept-url pattern="/user/*"    access="ROLE_USER" />
        <security:intercept-url pattern="/admin/*"   access="ROLE_ADMIN" />
        <security:intercept-url pattern="/*"         filters="none"/>

        <security:form-login login-page="/login"
                             default-target-url="/home" 
                             authentication-failure-url="/login?error=1"
                             always-use-default-target="true"/> 
    </security:http>

    <security:authentication-provider user-service-ref="userDetailsService" />

    <bean id='userDetailsService' class='com.security.UserDetailServiceImpl'>
        <property name='userdao' ref='userDao' />
    </bean>

</beans> 

Now we want to redirect user after authentication and authorization by user.

  • If a user has User role , it should go to home page of user, or
  • if a user has admin role then it should go to home page of admin .

For this , create a simple controller. After successfull authorization and authentication request.getUserPrinicipal will have the Prinicipal object containing userName which is set in UserDetailServiceImpl and we can check the roles by request.isUserInRole method.

In spring-security.xml , set target url to this controller and set always-use-default-target attribute to true in form-login tag , because we always want this controller to execute after user successfully authenticate the user. Sometimes if the request contains referer header, spring security redirect it to that previous link.That is why we set always-use-default-target attribute to true.

package com.controller;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.log4j.Logger;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.AbstractController;
import com.constants.Constants;
import com.model.UserRoles;
import com.util.CustomLogger;

/**
 * home controller to redirect users based on their role.
 * this is the home controller to redirect user to their home pages based on role name 
 * * for admin it should be /admin/home
 * * for user  it should be /user/home
 *
 * @author abhishek.somani
 */
public class HomeController extends AbstractController {

    @Override
    protected ModelAndView handleRequestInternal(HttpServletRequest  request,
                                                 HttpServletResponse arg1) 
                                                 throws Exception {
        if (request.isUserInRole("ROLE_USER")) {
            request.setAttribute("appendURL", "user");
            return new ModelAndView("user/home", "welcome ", null);
        }
        if (request.isUserInRole("ROLE_ADMIN")) {
            request.setAttribute("appendURL", "admin");
            return new ModelAndView("admin/home", "welcome ", null);
        }
        throw new Exception("No roles Detected");
    }
} 

Spring Security: custom userdetails

Source

I've gotten spring security 3 to work with all the default userDetails and userDetailsService and I know I can access the logged in user's username in a controller by using:

Authentication auth = SecurityContextHolder.getContext().getAuthentication();
String username = auth.getName(); //get logged in username
But there are two problems I can't figure out:

There are a lot of other user details I would like stored when a user logs in (such as DOB, gender, etc.) and to be accessible via the controllers later on.

  • What do I need to do so that the userDetails object that is created contains my custom fields?

I'm already calling HttpSession session = request.getSession(true); at the top of each of my methods in my controller.

  • Is it possible to store the logged in user's userDetails in a session
    upon login so that I don't need to also call
    Authentication auth = SecurityContextHolder.getContext().getAuthentication();
    at the beginning of every method?

Security-applicationContext.xml:

<global-method-security secured-annotations="enabled"></global-method-security>     
<http auto-config='true' access-denied-page="/access-denied.html">
    <!-- NO RESTRICTIONS -->        
    <intercept-url pattern="/login.html" access="IS_AUTHENTICATED_ANONYMOUSLY" />
    <intercept-url pattern="/*.html" access="IS_AUTHENTICATED_ANONYMOUSLY"  /> 
    <!-- RESTRICTED PAGES -->
    <intercept-url pattern="/admin/*.html" access="ROLE_ADMIN" />
    <intercept-url pattern="/member/*.html" access="ROLE_ADMIN, ROLE_STAFF" />

    <form-login login-page="/login.html"
                login-processing-url="/loginProcess"
                authentication-failure-url="/login.html?login_error=1"
                default-target-url="/member/home.html" />
    <logout logout-success-url="/login.html"/>
</http>

<authentication-manager>
    <authentication-provider>
        <jdbc-user-service data-source-ref="dataSource" 
                           authorities-by-username-query=
"SELECT U.username, UR.authority, U.userid FROM users U, userroles UR 
WHERE U.username=? AND U.roleid=UR.roleid LIMIT 1" />
        <password-encoder hash="md5"/>
    </authentication-provider>
</authentication-manager>

login.jsp:

<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<%@ taglib uri="http://tiles.apache.org/tags-tiles" prefix="tiles" %>
<%@ taglib uri="http://www.springframework.org/tags/form" prefix="form"%>

<tiles:insertDefinition name="header" />
<tiles:insertDefinition name="menu" />
<tiles:insertDefinition name="prebody" />

<h1>Login</h1>

<c:if test="${not empty param.login_error}">
    <font color="red"><c:out value="${SPRING_SECURITY_LAST_EXCEPTION.message}"/>.
    <br/><br /></font>
</c:if>
<form name="f" action="<c:url value='/loginProcess'/>" method="POST">
    <table>
        <tr>
            <td>User:</td>
            <td>
<input type='text' 
       name='j_username' 
       value='<c:if test="${not empty param.login_error}">
                  <c:out value="${SPRING_SECURITY_LAST_USERNAME}"/>
              </c:if>' />
            </td>
        </tr>
        <tr>
            <td>Password:</td>
            <td><input type='password' name='j_password' /></td>
        </tr>
        <tr>
            <td>&nbsp;</td>
            <td><input type="checkbox" name="_spring_security_remember_me" /> Remember Me</td>
        </tr>
        <tr>
            <td>&nbsp;</td>
            <td><input name="submit" type="submit" value="Login" /></td>
        </tr>
    </table>
</form>

<tiles:insertDefinition name="postbody" />
<tiles:insertDefinition name="footer" />

Q#1:

There are a couple possible approaches here.

  • Approach #1: If you have other attributes that you want to add to your UserDetails object, then you should provide your own alternate implementation of the UserDetails interface that ncludes those attributes along with corresponding getters and setters. This would require that you also provide your own alternate implementation of the UserDetailsService interface. This component would have to understand how to persist these additional attributes to the underlying datastore, or when reading from that datastore, would have to understand how to populate those additional attributes. You'd wire all of this up like so:
    <beans:bean id="userDetailsService" class="com.example.MyCustomeUserDetailsService">
        <!-- ... -->
    </beans:bean>

    <authentication-manager alias="authenticationManager">
        <authentication-provider ref="authenticationProvider"/>
    </authentication-manager>

    <beans:bean id="authenticationProvider" 
                class="org.springframework.security.authentication.dao.DaoAuthenticationProvider">
        <beans:property name="userDetailsService" ref="userDetailsService"/>
    </beans:bean>
  • Approache #2: Like me, you may find (especially over the span of several iterations) that you're better served to keep domain-specific user/account details separate from Spring Security specific user/account details. This may or may not be the case for you. But if you can find any wisdom in this approach, then you'd stick with the setup you have currently and add an additional User/Account domain object, corresponding repository/DAO, etc.

    If you want to retrieve the domain-specific user/account, you can do so as follows:

    User user = userDao.getByUsername(SecurityContextHolder.getContext()
                                                           .getAuthentication()
                                                           .getName());

Q#2:

Spring Security automatically stores the UserDetails in the session (unless you've explicitly taken steps to override that behavior). So there's no need for you to do this yourself in each of your controller methods. The SecurityContextHolder object you've been dealing with is actually populated (by SS) with SecurityContext including the Authentication object, UserDetails, etc. at the beginning of every request. This context is cleared at the end of each request, but the data always remains in the session.

It's worth noting, however, that it's not really a great practice to be dealing with HttpServletRequest, HttpSession objects, etc. in a Spring MVC controller if you can avoid it.

Spring almost always offers cleaner, more idiomatic means of achieving things without the need for doing so. The advantage to that would be that controller method signatures and logic cease to be dependent on things that are difficult to mock in a unit test (e.g. the HttpSession) and instead of dependent on your own domain objects (or stubs/mocks of those domain objects). This drastically increases the testability of your controllers... and thus increases the liklihood that you actually WILL test your controllers. :)

Hope this helps some.

Retrieving unique user data in Spring Security

Source

I have a table of items, user should be able to choose some of them, then these items are put in the other table (in the second table they are associated with the user who chose the items). I could associate items and users with a help of usernames, but I suppose it wouldn't be great. I wonder, what is a good way to do that.

I know there is an easy way to retrieve the username (<sec:authentication property="principal.username"/>), but today I learnt there is no such a way for an id.

  • What is a good way to solve this problem?
  • Should I implement UserDetails to have an opportunity to get each id?
  • Is there any good example of this implementation? I use Hibernate to communicate with the database.
  • Is there any other way of the identification (compound key consisted of values that are easy to retrieve or something like that)?

Answer

Yes you have to implement your own UserDetail which will have an id attribute.

You'll then fill in this object during authentication in your implementation of UserDetailService.

For example:

@Service("CustomUserDetailService")
public class CustomUserDetailService implements UserDetailsService{

    @Autowired
    private IUserDao userDao;

    @Override
    public UserDetails loadUserByUsername(String name) 
                                          throws UsernameNotFoundException, 
                                                 DataAccessException {
        User user = userDao.loadByName(name);
        CustomUserDetail customUserDetail = new CustomUserDetail();
        customUserDetail.setId(user.getId());
        customUserDetail.setPassword(user.getPassword());
        return customUserDetail ;
    }

After that you can retrieve anything from your principal :

<sec:authentication property="principal.id"/>
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