Created
July 17, 2017 16:51
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This is the solution to Codewars' KATA: Square(n)Sum
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| function squareSum(numbers){ | |
| var total = 0; | |
| for(var i = 0; i < numbers.length; i++) { | |
| total += numbers[i] * numbers[i]; | |
| } | |
| return total; |
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I found that my solution using loops worked;
function squareSum(numbers) {let sum = 0for( let i = 0; i < numbers.length; i++) {sum += numbers[i] **2}return sum}