Solution to share plz from bitsctf

share_plz_solve.py

import itertools
import hashlib

b=['6886e0d29007ca152880b30d73ca2adc',
  'e298fefb7e2f17e7ec4bdb1f491b871c',
  '56ead72536c569c0b4b275f0d6c394b5',
  '90263563551288d60ce0dfb9a73d37b3',
  'c5ac17d81bfd20d8ec4ec09e7d5d5ae3',
  '38d11d05e9168320b911be4375ce2159',
  'e668ea8a6e7d0687d2db728ffbd3c8c2',
  '3d7978850e30e9ceef58dd50ecd1e199',
  '620fe38f78a29a3bc51e11a35aaa2c2e',
  'c951ef807c0b0d740b067de83347d4a4',
  'eba6551ee6e5e76b4c6a98d46b446564']

d='abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789_{}'

def str_of_pem(p):
	return ''.join(p)

def fixstr(a):
	return a.encode('utf8')

def md5(s):
	return hashlib.md5(fixstr(s)).hexdigest()

def test(s):
	return md5(s) in b

def rank(a):
  return b.index(md5(a))


flag=list(filter(test, map(str_of_pem, itertools.product(d,repeat=4))))
flag.sort(key=rank)

print ''.join(flag)

# $ time python share_plz_solve.py 
# BITSCTF{unc0mpyl3_kn0w5_wh47_1_wr073_s0_s4d}

# real  0m20.059s
# user  0m19.699s
# sys 0m0.357s