lambda-bczp.sh

#!/usr/bin/env bash

if [ -z ${1+x} ]; then
    echo "Usage: $0 <source.go>"
    echo
    echo "Or in order to also publish:"
    echo "       $0 <source.go> <function name>"
    exit 2
fi

SRC=$1

echo "Building..."

grep "Arch Linux" /etc/os-release > /dev/null
# On Arch we need to specify CGO_ENABLED=0
# would it hurt to always do that? (when not using CGO)
if [ $? -eq 0 ]; then
    CGO_ENABLED=0 go build $SRC
else
    go build $SRC
fi

if [ $? -ne 0 ]; then
    echo "build failed. exiting..."
    exit 1
fi

echo "Starting the chmod step..."
EXE="${SRC%.*}"

chmod 711 "$EXE"
if [ $? -ne 0 ]; then
    echo "chmod failed. exiting..."
    exit 1
fi

echo "Creating the ZIP file..."
zip "$EXE.zip" "$EXE"

if [ $? -ne 0 ]; then
    echo "zip creation failed. exiting..."
    exit 1
fi

if [ -z ${2+x} ]; then
    echo "Done."
    exit 0
fi

echo "Running aws lambda update-function-code ..."

FUNCTION=$2
PWD=`pwd`

aws lambda update-function-code --function-name "$FUNCTION" --zip-file "fileb://$PWD/$EXE.zip" --publish

echo "Done."

Quick script that builds go binary, creates a zip file from it, and publishes it to AWS lambda. Only works with a single source code file.