Build maven com propriedade no application.yml

gistfile1.txt

Adicione essa entrada no pom.xml:

<dependency>
    <groupId>org.codehaus.mojo</groupId>
    <artifactId>properties-maven-plugin</artifactId>
    <version>1.0.0</version>
</dependency>

Dentro do contexto do build do seu pom.xml, configure o plugin com a seguinte entrada:

<build>
<plugin>
            <groupId>org.codehaus.mojo</groupId>
            <artifactId>properties-maven-plugin</artifactId>
            <version>1.0.0</version>
            <executions>
                <execution>
                    <phase>initialize</phase>
                    <goals>
                        <goal>read-project-properties</goal>
                    </goals>
                    <configuration>
                        <files>
                            <file>${basedir}/src/main/resources/application.yml</file>
                        </files>
                    </configuration>
                </execution>
            </executions>
</plugin>
</build>

Dentro do seu arquivo application.yml, se hipoteticamente a variável se chama myversion:

myversion=2.1

Dentro do pom, substitua o valor da tag version, pela variável filtrada ${myversion}:

<groupId>com.foo.app</groupId>
<artifactId>foo-app</artifactId>
<version>${myversion}</version> <!-- Essa versao aqui -->
<packaging>war</packaging>

Quando compilar, o artefato gerado será:

foo-app-2.1.war