Recursively remove .git folders

delete-git-recursively.sh

( find . -type d -name ".git" && find . -name ".gitignore" && find . -name ".gitmodules" ) | xargs rm -rf

Nice! Thanks.

If you want this to work with file & directory names that have whitespace in them you can change the delimiter to '\n':

( find . -type d -name ".git" && find . -name ".gitignore" && find . -name ".gitmodules" ) | xargs -d '\n' rm -rf

Since MacOS High Sierra 10.13+ has an installed xargs that doesn't support the -d argument, you can use -0 in its place.

( find . -type d -name ".git" && find . -name ".gitignore" && find . -name ".gitmodules" ) | xargs -0 rm -rf

Thanks. I added .gitattributes
`( find . -type d -name ".git" && find . -name ".gitignore" && find . -name ".gitmodules" && find . -name ".gitattributes" ) | xargs rm -rf

I see a couple of problems here.

1. Separating the find commands with && means that the subsequent ones will only run if the last one had an exitcode == 0. That might not always be the case.

2. Lots of forking (find -> find -> find -> find -> xargs). That could be simplified and done without any pipes:

find . \( -name ".git" -o -name ".gitignore" -o -name ".gitmodules" -o -name ".gitattributes" \) -exec rm -rf -- {} +

Great! Thank you!

smart guys!