JavaScript FizzBuzz example

FizzBuzz.js

'use strict';

/*
 * Complete the 'fizzBuzz' function below.
 *
 * The function accepts INTEGER n as parameter.
 */

function fizzBuzz(n) {
    if(typeof n !== 'number') {
      console.log("The input must be of Type Number.")
      return
    }
    let result = '';
    for(let i = 1; i < n + 1; i++) {

        if ((i % 3 == 0) && (i % 5 == 0)) {
            result.concat('\n', 'FizzBuzz')
        }
        else if (i % 5 == 0) {
            result.concat('\n', 'Buzz')
        }
        else if (i % 3 == 0) {
            result.concat('\n', 'Fizz');
        }
        else {
            result.concat('\n', i);
        }
    };
    return console.log(result);
}

function main() {
    const n = parseInt(readLine().trim(), 10);

    fizzBuzz(n);
}