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echo "Please pick up the following from the store: $groceries[0]";

This isn't going to work by the way: inserting a variable's value into a string "like $x this" only works with a simple variable such as $x – for array elements you have two other options:

1. String concatenation:

   echo "buy ".$groceries[0]." at the store";
   

2. save in a variable beforehand:

   $first = $groceries[0];
   echo "buy $first at the store";
   

This comment was previously published here but later revised because it's not correct.