Created
October 5, 2019 04:25
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#include<bits/stdc++.h> | |
using namespace std; | |
#define ll long long | |
int prime[100005],pcheck[100005],ind; | |
void seive(ll n) | |
{ | |
ll i,j,k; | |
prime[ind++]=2; | |
for(i=4;i<100000;i+=2) | |
{ | |
pcheck[i]=1; | |
} | |
for(i=3;i<=100000;i+=2) | |
{ | |
if(!pcheck[i]) | |
{ | |
prime[ind++]=i; | |
if(i*i>100000) | |
continue; | |
for(j=i*i;j<=100000;j+=2*i) | |
{ | |
pcheck[j]=1; | |
} | |
} | |
} | |
} | |
int main () | |
{ | |
ll tc,idd=0,n,a,i,b,l,d,c,c1,c2,c3,num; | |
seive(100000); | |
scanf("%lld",&tc); | |
while(idd<tc){ | |
num=1; | |
scanf("%lld %lld %lld",&a,&b,&l); | |
printf("Case %lld: ",++idd); | |
if(l%a!=0 || l%b!=0) | |
{ | |
printf("impossible\n"); | |
continue; | |
} | |
d=(a/__gcd(a,b))*b; | |
for(i=0;prime[i]<=l;i++) | |
{ | |
c1=0,c2=0,c3=0; | |
while(l%prime[i]==0) | |
{ | |
l/=prime[i]; | |
c1++; | |
} | |
while(d%prime[i]==0) | |
{ | |
d/=prime[i]; | |
c2++; | |
} | |
if(c2==c1) | |
{ | |
c3=0; | |
} | |
else | |
{ | |
c3=c1; | |
while(c3--) | |
{ | |
num*=prime[i]; | |
} | |
} | |
} | |
printf("%lld\n",num); | |
} | |
return 0; | |
} |
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