answer1.swift

func isSubsetOf(arr1: [String], arr2: [String]) -> Bool {
    var result = false

    arr2.forEach { (str) in
        conditional: if (arr1.contains(str)) {
            result = true
        } else {
            result = false
            break conditional
        }
    }

    return result

}

// Faster way using built in set function which relies on Hashtables

func isSubsetOfFast(arr1: [String], arr2: [String]) -> Bool{

    var result = false

    let set1 = Set(arr1)
    let set2 = Set(arr2)

    if (set2.isSubset(of: set1)){
        result = true
    }

    return result

}

let testArr1 = ["A","B","C","D","E"]
let testArr2 = ["A","E","D"]

let testArr3 = ["A","B","C","D","E"]
let testArr4 = ["A","D","Z"]

print(isSubsetOf(arr1: testArr3, arr2: testArr4))
print(isSubsetOfFast(arr1: testArr3, arr2: testArr4))