Solution to puzzle at http://www.recruitahacker.net/Puzzle

puzzle.py

#!/usr/bin/python3
# Vigenere Cipher solver thing
# by fattire / github.com/fat-tire
# for puzzle at http://www.recruitahacker.net/Puzzle
# For more, see:  https://en.wikipedia.org/wiki/Vigen%C3%A8re_cipher

import string

key       = "aaaaaaaaaaaaaaaaaa"  # Gotta start somewhere
newkey    = ""
encrypted = "Kozgtyuycwtzfvg, z"
target    = "Congratulations, i"  # I figured this was the first word.

for i, c in enumerate(key):
    if encrypted[i] not in string.ascii_letters:
        continue
    diff = ord(encrypted[i]) - ord(target[i])
    if (diff < 0):
        diff = diff + len(string.ascii_lowercase) #26
    newkey += chr(ord(c) + diff)

print(newkey)

I am getting very confused as I am not seeing where or how, newkey become iamacyberworrier. if I had an encrypted message of
Ccoheal ieu w qwu tcb
how would I structure the code to decrypt it?

@Ladysman213,
They changed the cipher, so this solution no longer works with the new cipher. You could probably rework the code a little bit to crack the new one though.