Python code review

Alien Language solution.py

"""
Alien Language - solution
Google Code Jam 2009 - Qual round
Problem available at
http://code.google.com/codejam/contest/90101/dashboard#s=p0

By Tim Lee, 28/04/14

Input as L D N, followed by D dictionary words, N 'patterns' to decode
"""

f = open('A-small-practice.in', 'r')
g = open('A-small-practice-output.txt', 'w')

L, D, N = (int(x) for x in f.readline().split())


def make_dictionary():
    """Creates dictionary from list in file"""
    dictionary = []
    for i in range(D):
        dictionary.append((f.readline()).rstrip('\n'))
    return dictionary


def format_pattern(raw_pattern):
    """Turns pattern string into a more easily iterable form.
    Removes parentheses and turns letters in between them into a
    sub-list"""
    pattern_formatted = []
    bracketed_letters = []
    in_brackets = False

    for char in raw_pattern:
        if (char != "(" and char != ")" and in_brackets is not True):
            pattern_formatted.append(char)

        elif char == "(":
            in_brackets = True

        elif char == ")":
            pattern_formatted.append(bracketed_letters)
            bracketed_letters = []
            in_brackets = False

        elif in_brackets is True:
            bracketed_letters.append(char)

    return pattern_formatted


def match_words(pattern_formatted, dictionary):
    """Takes the formatted pattern and dictionary and returns the number of
    pattern configurations that match with dictionary words"""
    matched_words = 0
    for word in range(D):
        for letter in range(L):
            match = False
            for subletter in range(len(pattern_formatted[letter])):
                if (dictionary[word][letter] ==
                        pattern_formatted[letter][subletter]):
                    match = True
            if match is False:
                break
        if match is True:
            matched_words += 1
    return matched_words


def write_result(case, matched_words):
    """Writes the result in required format to file and prints to console"""
    print("Case #" + case + ": " + matched_words)
    g.write("Case #" + case + ": " + matched_words + "\n")


DICTIONARY = make_dictionary()

for n in range(N):
    #Iterates through each pattern to test for matching words

    pattern = (f.readline()).rstrip('\n')
    matched_words = match_words(format_pattern(pattern), DICTIONARY)
    write_result(str(n+1), str(matched_words))

f.close()
g.close()