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golang linked list implementation
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package main | |
import "fmt" | |
type Node struct { | |
prev *Node | |
next *Node | |
key interface{} | |
} | |
type List struct { | |
head *Node | |
tail *Node | |
} | |
func (L *List) Insert(key interface{}) { | |
list := &Node{ | |
next: L.head, | |
key: key, | |
} | |
if L.head != nil { | |
L.head.prev = list | |
} | |
L.head = list | |
l := L.head | |
for l.next != nil { | |
l = l.next | |
} | |
L.tail = l | |
} | |
func (l *List) Show() { | |
list := l.head | |
for list != nil { | |
fmt.Printf("%+v ->", list.key) | |
list = list.next | |
} | |
fmt.Println() | |
} | |
func Show(list *Node) { | |
for list != nil { | |
fmt.Printf("%v ->", list.key) | |
list = list.next | |
} | |
fmt.Println() | |
} | |
func ShowBackwards(list *Node) { | |
for list != nil { | |
fmt.Printf("%v <-", list.key) | |
list = list.prev | |
} | |
fmt.Println() | |
} | |
// 1 -> 2 -> 3 -> 4 -> nil | |
// nil <- 1 <- 2 <- 3 <- 4 | |
func (l *List) Reverse() { | |
curr := l.head | |
var prev *Node | |
l.tail = l.head | |
for curr != nil { | |
next := curr.next | |
curr.next = prev | |
prev = curr | |
curr = next | |
} | |
l.head = prev | |
Show(l.head) | |
} | |
func main() { | |
l := List{} | |
l.Insert(1) | |
l.Insert(2) | |
l.Insert(3) | |
l.Insert(4) | |
l.Insert(5) | |
l.Insert(6) | |
fmt.Printf("head: %v\n", l.head.key) | |
fmt.Printf("tail: %v\n", l.tail.key) | |
l.Show() | |
l.Reverse() | |
fmt.Printf("head: %v\n", l.head.key) | |
fmt.Printf("tail: %v\n", l.tail.key) | |
} |
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