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#!/usr/bin/env python2 | |
# lrdcq | |
# usage python2 unwxapkg.py filename | |
import sys, os | |
import struct | |
class WxapkgFile(object): | |
nameLen = 0 | |
name = "" | |
offset = 0 | |
size = 0 | |
if len(sys.argv) < 2: | |
print 'usage: unwxapkg.py filename' | |
exit() | |
with open(sys.argv[1], "rb") as f: | |
root = os.path.dirname(os.path.realpath(f.name)) | |
name = os.path.basename(f.name) + '_dir' | |
if len(sys.argv) > 2: | |
name = sys.argv[2] | |
#read header | |
firstMark = struct.unpack('B', f.read(1))[0] | |
print 'first header mark = ' + str(firstMark) | |
info1 = struct.unpack('>L', f.read(4))[0] | |
print 'info1 = ' + str(info1) | |
indexInfoLength = struct.unpack('>L', f.read(4))[0] | |
print 'indexInfoLength = ' + str(indexInfoLength) | |
bodyInfoLength = struct.unpack('>L', f.read(4))[0] | |
print 'bodyInfoLength = ' + str(bodyInfoLength) | |
lastMark = struct.unpack('B', f.read(1))[0] | |
print 'last header mark = ' + str(lastMark) | |
if firstMark != 0xBE or lastMark != 0xED: | |
print 'its not a wxapkg file!!!!!' | |
exit() | |
fileCount = struct.unpack('>L', f.read(4))[0] | |
print 'fileCount = ' + str(fileCount) | |
#read index | |
fileList = [] | |
for i in range(fileCount): | |
data = WxapkgFile() | |
data.nameLen = struct.unpack('>L', f.read(4))[0] | |
data.name = f.read(data.nameLen) | |
data.offset = struct.unpack('>L', f.read(4))[0] | |
data.size = struct.unpack('>L', f.read(4))[0] | |
print 'readFile = ' + data.name + ' at Offset = ' + str(data.offset) | |
fileList.append(data) | |
#save files | |
for d in fileList: | |
d.name = '/' + name + d.name | |
path = root + os.path.dirname(d.name) | |
if not os.path.exists(path): | |
os.makedirs(path) | |
w = open(root + d.name, 'w') | |
f.seek(d.offset) | |
w.write(f.read(d.size)) | |
w.close() | |
print 'writeFile = ' + root + d.name | |
f.close() |
Amazing tool, Great job!
You can find a python3 version here
解出来是 一些 .html 文件,编辑器都打不开。。
请问怎么获取小程序的appID?
解压出来的都是html文件,怎么用呢
同问 HTML文件有还原的工具吗
Traceback (most recent call last):
File "unwxapkg.py", line 78, in
w = open(root + d.name, 'w')
IOError: [Errno 22] invalid mode ('w') or filename: 'xxx.wxapkg_dir/res/\xe6\xb0\x94\xe6\xb3\xa1\xe7\x8b\x97\xe7\x99\xbd\xe8\x84\xb8.png'
Traceback (most recent call last):
File "unwxapkg.py", line 31, in
firstMark = struct.unpack('B', f.read(1))[0]
struct.error: unpack requires a string argument of length 1
这个是啥毛病....
同问html后面怎么解码
https://wxbug.cn 这里可直接上传解析
现在微信小游戏里的图片加密了?能破吗
如果出现中文文件名会报错,可以试试这样( line: 65 && line: 78):
# line 65
print 'readFile = ' + data.name.decode('utf-8') + ' at Offset = ' + str(data.offset)
# line 78
filepath = unicode(root + d.name,'utf8')
w = open(filepath, 'w')
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原始代码链接: http://lrdcq.com/me/read.php/66.htm