Created
November 12, 2014 04:01
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Edit Distance
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/* | |
Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2. (each operation is counted as 1 step.) | |
You have the following 3 operations permitted on a word: | |
a) Insert a character | |
b) Delete a character | |
c) Replace a character | |
*/ | |
/* Dynamic Programming | |
Example. abcee vs abddd | |
0 | a | b | c | e | e | |
0| 0 1 2 3 4 5 | |
a| 1 0 1 2 3 4 | |
b| 2 1 0 1 2 3 | |
d| 3 2 1 1 2 3 | |
d| 4 3 2 2 2 3 | |
d| 5 4 3 3 3 3 | |
*/ | |
public class Solution { | |
public int minDistance(String word1, String word2) { | |
int[][] a = new int[word1.length()+1][word2.length()+1]; | |
for(int i = 0; i < word1.length()+1; i++) { | |
a[i][0] = i; | |
} | |
for(int j = 0; j < word2.length()+1; j++) { | |
a[0][j] = j; | |
} | |
for(int j = 1 ; j < word2.length() + 1; j++) { | |
for(int i = 1; i < word1.length() + 1; i++) { | |
if(word1.charAt(i-1) == word2.charAt(j-1)){ | |
a[i][j] = a[i-1][j-1]; | |
} else { | |
a[i][j] = Math.min(a[i-1][j-1], Math.min(a[i-1][j],a[i][j-1])) + 1; | |
} | |
} | |
} | |
return a[word1.length()][word2.length()]; | |
} | |
} |
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