Multiplication persistance

per.py

def per(n, print_steps=False):
    steps = 0
    while n >= 10:
        sum = 1
        while n > 0:
            sum *= n % 10
            n //= 10

        n = sum
        steps += 1
        if print_steps:
            print(f"{steps} - {n}")

    return steps

print(per(277777788888899, True))