Send PHP Debug Information to Javascript Console

phog.php

<?php

/**  
* Send PHP debug data to JS console.log
* Example:
*       <code>
*           phog(compact('table', 'id'), __FILE__);
*       </code>
*
*       Which outputs the following in the console:
*       ===== START PHP DUMP =====
*       Output From /Users/jeremy/apollo/apollo/core/Admin/AdminController.php
*       table: pages
*       id: 9226
*       ===== END PHP DUMP =====
*       
* @param Array $vars Variables to dump as an associative array (compact() recommended).
* @param String $source Local source where phog() was called. Use __FILE__ in most circumstances.
* @author J.M. Usher <jeremy.usher@gmail.com>
* @return void 
*/
function phog(array $vars, $source) {

    $out = array();
    $out[] = '===== START PHP DUMP =====';
    $out[] = "Output From " . $source;
    
    foreach($vars as $name=>$value) {
       
        $out[] = $name . ': ' . print_r($value, true); 

    }

    $out[] = '===== END PHP DUMP =====';
    $out = json_encode(implode("\r\n", $out));
    
    print "<script> console.log($out); </script>";

}