get next even or odd number given n

nextNumOfType.js

nextNumOfType = (n, d) => {
	let opts = {true: {'even': 2,'odd': 1}, false:{'even': 1,'odd': 2}}
	return n + opts[n%2 == 0][d];
}

nextNumOfType(3,'odd')  //  5
nextNumOfType(3,'even') //  4
nextNumOfType(4,'odd')  //  5
nextNumOfType(4,'even') //  6