Project Euler problem #1

pe1.py

'''
If we list all the natural numbers below 10 that are multiples
of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.
'''

from time import time

def pe1():
    return (sum([n for n in range(1, 1000) if n % 3 == 0 or n % 5 == 0]))

if __name__ == "__main__":
    start = time()
    x = pe1()
    print (x, time() - start)