Check if items in list alternatingly match keys in two dicts

alternatingtest.py

# fake YAML input data (only keys matter)
connectors = {'A': [1,2,3], 'B': [1,2,4], 'C': [3,6,7]}
cables     = {'X': [4,4,4], 'Y': [4,5,6], 'Z': [9,9,9]}

# list to check, should alternatingly contain connector and cable keys, may start with either
listy = ['A','X','B','Y','C']

conkeys = list(connectors.keys())
cblkeys = list(cables.keys())

print('conkeys', conkeys)
print('cblkeys', cblkeys)

found_in_con = [item in conkeys for item in listy] # should contain alternating True and False
found_in_cbl = [item in cblkeys for item in listy] # should contain alternating False and True (reversed)

print('found_in_con', found_in_con)
print('found_in_cbl', found_in_cbl)

alternating = ([True, False] * ((len(listy)+1) // 2))[0:len(listy)] # generate alternating True and False list, with length = len(listy)

check1 = [item == check for (item, check) in zip(found_in_con, alternating)] # should contain all True if list starts with connector, all False if list starts with cable, both True and False if it does not alternate properly
check2 = [item != check for (item, check) in zip(found_in_con, alternating)] # same as above, but with inverted logic

print('check1', check1)
print('check2', check2)

starts_with_connector = all(check1) and not any(check2)
starts_with_cable     = all(check2) and not any(check1)

OK = starts_with_connector or starts_with_cable

print('OK?', OK)

I like it! I'll build on that. Thanks!