We were asked... how do you count the number of active user jobs "right now" and see the answer ordered by highest to lowest count. The answer is found below and I've included a version of the SQL that will work for anyone still using IBM i 7.1.

Count active user jobs.sql

--
-- description: Count the number of active user jobs in the system
-- minvrm: v7r2m0
--
select authorization_name as user_name, count(*) as active_job_count
  from table (
      qsys2.active_job_info()) j
  where job_type <> 'SYS' and job_status not in ('PSRW') and
        j.authorization_name not in (select user_name
            from qsys2.user_info
            where user_creator = '*IBM')
  group by authorization_name
  order by 2 desc;
  
--
-- description: Count the number of active user jobs in the system 
-- minvrm: v7r1m0
--  
select authorization_name as user_name, count(*) as active_job_count
  from table (
      qsys2.active_job_info('NO', '', '', '')
    ) j
  where job_type <> 'SYS' and job_status not in ('PSRW') and
        j.authorization_name not in (select user_name
            from qsys2.user_info
            where user_creator = '*IBM')
  group by authorization_name
  order by 2 desc;