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string getLongestCommonSubString(string a, string b) | |
{ | |
/* | |
dp[i, j] 为a[0, i - 1] 与 b[0, j - 1]末尾连续相等元素的数量 | |
dp[i, j] = 0 (a[i] != b[j]) | |
dp[i, j] = dp[i - 1, j - 1] + 1 (a[i] == b[j]) | |
*/ | |
vector<vector<int>> dp(a.length() + 1, vector<int>(b.length() + 1, 0)); | |
int index = 0; | |
int maxLen = 0; | |
for (int i = 1; i <= a.length(); i++) { | |
for (int j = 1; j <= b.length(); j++) { | |
if (a[i - 1] != b[j - 1]) { | |
dp[i][j] = 0; | |
} | |
else { | |
dp[i][j] = dp[i - 1][j - 1] + 1; | |
if (dp[i][j] > maxLen) { | |
maxLen = dp[i][j]; | |
index = i - 1; | |
} | |
} | |
} | |
} | |
return a.substr(index - maxLen + 1, maxLen); | |
} | |
void getLongestCommonSubStrigTest() | |
{ | |
string a = "cuiolf1234567cpomge12345678abcc"; | |
string b = "uzvldmf1234567vhhaocjl12345678accc"; | |
cout << a << endl; | |
cout << b << endl; | |
cout << "common: " << getLongestCommonSubString(a, b) << endl; | |
} | |
string getLongestCommonSubsequence(string a, string b) | |
{ | |
/* | |
dp[i, j]表示a[0, i - 1]与b[0, j - 1]最长公共序列的长度 | |
dp[i, j] = 0 (i == 0 || j == 0) | |
dp[i, j] = dp[i -1, j - 1] + 1 a[i] == b[j] | |
dp[i, j] = max(dp[i - 1, j] ,dp[i, j -1]) a[i] != b[j] | |
*/ | |
vector<vector<int>> dp(a.length() + 1, vector<int>(b.length() + 1)); | |
for (int i = 0; i <= a.length(); i++) { | |
for (int j = 0; j <= b.length(); j++) { | |
if (i == 0 || j == 0) { | |
dp[i][j] = 0; | |
} | |
else { | |
if (a[i - 1] == b[j - 1]) { | |
dp[i][j] = dp[i - 1][j - 1] + 1; | |
} | |
else { | |
dp[i][j] = max(dp[i - 1][j], dp[i][j - 1]); | |
} | |
} | |
} | |
} | |
// show dp | |
//for (vector<int> row : dp) { | |
// for (int i : row) { | |
// cout << i << " "; | |
// } | |
// cout << endl; | |
//} | |
// create LCS | |
string lcs = ""; | |
int row = a.length(); | |
int col = b.length(); | |
int len = dp[row][col]; | |
while (len) { | |
//cout << "(" << row << ", " << col << ")" << endl; | |
if (a[row - 1] == b[col - 1]) { | |
lcs.append(1, a[row - 1]); | |
len--; | |
row--; | |
col--; | |
} | |
else { | |
if (dp[row - 1][col] == len) { | |
row--; | |
} | |
else { | |
col--; | |
} | |
} | |
} | |
reverse(lcs.begin(), lcs.end()); | |
return lcs; | |
} | |
void getLongestCommonSubsequenceTest() | |
{ | |
string a = "c1z2xcc3te4bjt5htu6dfa"; | |
string b = "j1lg2jk3f4jk5ky6vcz"; | |
cout << a << endl; | |
cout << b << endl; | |
cout << "lcs: " << getLongestCommonSubsequence(a, b) << endl; | |
} |
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