Flow Matching in 100 LOC

flow_matching.py

#!/usr/bin/env python

import math
import matplotlib.pyplot as plt
import torch
import torch.nn as nn

from sklearn.datasets import make_moons
from torch import Tensor
from tqdm import tqdm
from typing import *
from zuko.utils import odeint


def log_normal(x: Tensor) -> Tensor:
    return -(x.square() + math.log(2 * math.pi)).sum(dim=-1) / 2


class MLP(nn.Sequential):
    def __init__(
        self,
        in_features: int,
        out_features: int,
        hidden_features: List[int] = [64, 64],
    ):
        layers = []

        for a, b in zip(
            (in_features, *hidden_features),
            (*hidden_features, out_features),
        ):
            layers.extend([nn.Linear(a, b), nn.ELU()])

        super().__init__(*layers[:-1])


class CNF(nn.Module):
    def __init__(self, features: int, freqs: int = 3, **kwargs):
        super().__init__()

        self.net = MLP(2 * freqs + features, features, **kwargs)

        self.register_buffer('freqs', torch.arange(1, freqs + 1) * torch.pi)

    def forward(self, t: Tensor, x: Tensor) -> Tensor:
        t = self.freqs * t[..., None]
        t = torch.cat((t.cos(), t.sin()), dim=-1)
        t = t.expand(*x.shape[:-1], -1)

        return self.net(torch.cat((t, x), dim=-1))

    def encode(self, x: Tensor) -> Tensor:
        return odeint(self, x, 0.0, 1.0, phi=self.parameters())

    def decode(self, z: Tensor) -> Tensor:
        return odeint(self, z, 1.0, 0.0, phi=self.parameters())

    def log_prob(self, x: Tensor) -> Tensor:
        I = torch.eye(x.shape[-1], dtype=x.dtype, device=x.device)
        I = I.expand(*x.shape, x.shape[-1]).movedim(-1, 0)

        def augmented(t: Tensor, x: Tensor, ladj: Tensor) -> Tensor:
            with torch.enable_grad():
                x = x.requires_grad_()
                dx = self(t, x)

            jacobian = torch.autograd.grad(dx, x, I, create_graph=True, is_grads_batched=True)[0]
            trace = torch.einsum('i...i', jacobian)

            return dx, trace * 1e-2

        ladj = torch.zeros_like(x[..., 0])
        z, ladj = odeint(augmented, (x, ladj), 0.0, 1.0, phi=self.parameters())

        return log_normal(z) + ladj * 1e2


class FlowMatchingLoss(nn.Module):
    def __init__(self, v: nn.Module):
        super().__init__()

        self.v = v

    def forward(self, x: Tensor) -> Tensor:
        t = torch.rand_like(x[..., 0, None])
        z = torch.randn_like(x)
        y = (1 - t) * x + (1e-4 + (1 - 1e-4) * t) * z
        u = (1 - 1e-4) * z - x

        return (self.v(t.squeeze(-1), y) - u).square().mean()


if __name__ == '__main__':
    flow = CNF(2, hidden_features=[64] * 3)

    # Training
    loss = FlowMatchingLoss(flow)
    optimizer = torch.optim.Adam(flow.parameters(), lr=1e-3)

    data, _ = make_moons(16384, noise=0.05)
    data = torch.from_numpy(data).float()

    for epoch in tqdm(range(16384), ncols=88):
        subset = torch.randint(0, len(data), (256,))
        x = data[subset]

        loss(x).backward()

        optimizer.step()
        optimizer.zero_grad()

    # Sampling
    with torch.no_grad():
        z = torch.randn(16384, 2)
        x = flow.decode(z)

    plt.figure(figsize=(4.8, 4.8), dpi=150)
    plt.hist2d(*x.T, bins=64)
    plt.savefig('moons_fm.pdf')

    # Log-likelihood
    with torch.no_grad():
        log_p = flow.log_prob(data[:4])

    print(log_p)

To paraphrase, I don't want the computation of log-absolute-determinant of the Jacobian (ladj) to influence the step size of the solver. But because the trace has high magnitude compared to the derivative (dx), it does influence it (and makes it much slower) in practice. To mitigate this, I multiply trace by a factor 10−2, and at the end multiply the ladj by the inverse factor 102.

Hi @francois-rozet, should I change this factor when dealing with other data (e.g. image embedding), or keep it the same ?

Hello @thangld201, the best would be to try different values for the factor (basically its a tradeoff between log-prob accuracy and efficiency) and pick what suits your needs. Note that this code expects x to be a vector or a batch of vectors. If x has the shape of an image it will likely not work.

@francois-rozet Thanks for your answer. So if the factor is lower (e.g. 1e-6), it gets less accurate but faster ?

Exactly, but potentially much less accurate, while being marginally faster. That's why you should try a few values (with the same input, to compare the results).

For decoding - I don't see anything that necessitates z being from a normal distribution. Does this mean z can be sampled from any probability distribution?

@jenkspt I would think so, I am aware of at least one study (in the context of data unfolding in High Energy Physics) that does data to data with this formulation. https://arxiv.org/abs/2311.17175
I have to think a bit deeply if that makes sense, though. (Results look good nonetheless)

@jenkspt As long as the distribution of $z$ is the same during training and sampling, I think it should work.