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@freak4pc
Last active May 21, 2024 11:53
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Israeli ID Validator (Javascript)
function isValidIsraeliID(id) {
var id = String(id).trim();
if (id.length > 9 || id.length < 5 || isNaN(id)) return false;
// Pad string with zeros up to 9 digits
id = id.length < 9 ? ("00000000" + id).slice(-9) : id;
return Array
.from(id, Number)
.reduce((counter, digit, i) => {
const step = digit * ((i % 2) + 1);
return counter + (step > 9 ? step - 9 : step);
}) % 10 === 0;
}
// Usage
["1234567890","001200343", "231740705", "339677395"].map(function(e) {
console.log(e + " is " + (isValidIsraeliID(e) ? "a valid" : "an invalid") + " Israeli ID");
});
// Outputs:
// 1234567890 is an invalid Israeli ID
// 001200343 is an invalid Israeli ID
// 231740705 is a valid Israeli ID
// 339677395 is a valid Israeli ID
extension String {
func isValidIsraeliID() -> Bool {
let trimmed = trimmingCharacters(in: .whitespacesAndNewlines)
let isNumeric = rangeOfCharacter(from: CharacterSet.decimalDigits.inverted) == nil
guard 1...9 ~= trimmed.count,
isNumeric else { return false }
let neededZeros = 9 - trimmed.count
let tested = String(repeating: "0", count: neededZeros) + trimmed
return tested.enumerated()
.reduce(into: 0) { counter, args in
let (idx, char) = args
guard let digit = char.wholeNumberValue else { return }
let step = digit * ((idx % 2) + 1)
counter += step > 9 ? step - 9 : step
} % 10 == 0
}
}
@adi518
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adi518 commented Apr 12, 2018

This is an ancient algo that's present many years: https://gist.github.com/adi518/84214b150357291e7523179c331f3bc1

I slightly updated it, but it misses padding. My point though, does it differ logic-wise? If not, I guess you should put yours on npm. There's one entry on npm atm, but it lacks padding and source is not as good. :)

@adi518
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adi518 commented Apr 15, 2018

Don't need var here: var id = String(id).trim();.

@landesm
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landesm commented Jan 30, 2021

hello, is there anyway to turn this into a regexp ?
thanks

@freak4pc
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Author

@landesm Don't see how. Regex is for matching, not complex computation.

@matantech
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@freak4pc
Thank you for the swift version!

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