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Let's call (r_i)_{i>=0} the sequence of the ranks of (A^i)_{i>=0}. | |
For any i>=0, the image of A^{i+1} is a subspace of the image of A^{i}. | |
Our sequence of ranks (r_i) is non-increasing. | |
If for a given i, we have rank of r^i = r^{i+1}, this means that A restricted to the image | |
of {A^i} is bijective. As a result for all j > i, the image of {A^j} is exactly the image of {A^i}. | |
In other words, (r_i) is a sequence of non-negative integers that | |
- starts at n | |
- might be stricly decreasing for a while | |
- stagnates after a given value L. | |
Assuming L=0, it means it means that during the strictly decreasing phase, it went down from n to 0. | |
The slowest we can decrease is by 1, hence it would take at most n steps... A^n = 0. |
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