Created
March 10, 2019 07:11
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Leetcode 773 BFS_1
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class Solution { | |
private: | |
struct State { | |
string key; | |
vector<int> board; | |
vector<int> indices; | |
}; | |
string encode(vector<int>& vec) { | |
string result = ""; | |
for (int x : vec) { | |
result += (char)(x + '0'); | |
} | |
return result; | |
} | |
vector<int> flatten(vector<vector<int>>& board) { | |
vector<int> result; | |
for (auto& vec: board) { | |
result.insert(result.end(), vec.begin(), vec.end()); | |
} | |
return result; | |
} | |
int bfs(State& source, State& target, int n, int m) { | |
vector<int> directions = {-1, 0, 1, 0, 0, -1, 0, 1}; | |
unordered_map<string, int> depths; | |
queue<State> q; | |
q.push(source); | |
depths[source.key] = 0; | |
while (!q.empty() && depths.find(target.key) == depths.end()) { | |
State curState = q.front(); | |
q.pop(); | |
int curdepth = depths[curState.key]; | |
int center = curState.indices[0]; | |
int cx = center % m; | |
int cy = center / m; | |
for (int i = 0; i < directions.size(); i += 2) { | |
int nx = cx + directions[i]; | |
int ny = cy + directions[i + 1]; | |
if (nx < 0 || ny < 0 || nx >= m || ny >= n) { | |
continue; | |
} | |
State nextState = curState; | |
int nextPos = ny * m + nx; | |
swap(nextState.indices[curState.board[center]], nextState.indices[curState.board[nextPos]]); | |
swap(nextState.board[center], nextState.board[nextPos]); | |
nextState.key = encode(nextState.board); | |
if (depths.find(nextState.key) == depths.end()) { | |
depths[nextState.key] = curdepth + 1; | |
q.push(nextState); | |
} | |
} | |
} | |
return depths.find(target.key) == depths.end() ? -1 : depths[target.key]; | |
} | |
public: | |
int slidingPuzzle(vector<vector<int>>& board) { | |
State source; | |
State target; | |
source.board = flatten(board); | |
target.board = {1, 2, 3, 4, 5, 0}; | |
source.key = encode(source.board); | |
target.key = encode(target.board); | |
source.indices.resize(6); | |
target.indices.resize(6); | |
for (int i = 0; i < 6; ++i) { | |
source.indices[source.board[i]] = i; | |
target.indices[target.board[i]] = i; | |
} | |
return bfs(source, target, board.size(), board[0].size()); | |
} | |
}; |
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