Created
October 18, 2015 18:03
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/** | |
* Definition for singly-linked list. | |
* public class ListNode { | |
* int val; | |
* ListNode next; | |
* ListNode(int x) { val = x; } | |
* } | |
*/ | |
public class Solution { | |
public ListNode sortList(ListNode head) { | |
if (head == null || head.next == null) { | |
return head; | |
} | |
ListNode slow = head; | |
ListNode fast = head; | |
while (fast.next != null && fast.next.next != null) { | |
slow = slow.next; | |
fast = fast.next.next; | |
} | |
ListNode head1 = head; | |
ListNode head2 = slow.next; | |
slow.next = null; | |
head1 = sortList(head1); | |
head2 = sortList(head2); | |
return merge(head1, head2); | |
} | |
private ListNode merge(ListNode head1, ListNode head2) { | |
if (head1 == null) { | |
return head2; | |
} | |
if (head2 == null) { | |
return head1; | |
} | |
ListNode dummyNode = new ListNode(0); | |
ListNode curr = dummyNode; | |
while (head1 != null && head2 != null) { | |
if (head1.val <= head2.val) { | |
curr.next = head1; | |
head1 = head1.next; | |
} else { | |
curr.next = head2; | |
head2 = head2.next; | |
} | |
curr = curr.next; | |
} | |
curr.next = head1 == null ? head2 : head1; | |
return dummyNode.next; | |
} | |
} |
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