Locate photo with GPSInfo in. Just a test. Based on Erans' work get_lat_lon_exif_pil.py.

GPStracker.py

from PIL import Image, ExifTags
import webbrowser

def converter(value):
	d0 = value[0][0]
	d1 = value[0][1]
	d = float(d0) / float(d1)
	m0 = value[1][0]
	m1 = value[1][1]
	m = float(m0) / float(m1)
	s0 = value[2][0]
	s1 = value[2][1]
	s = float(s0) / float(s1)
	return d + (m / 60.0) + (s / 3600.0)
	
def inList(a, b):
	for item in a:
		if item not in b.keys():
			return False
		else:
			return True

img = Image.open('fileName')

exif = {
	ExifTags.TAGS[k]: v
    for k, v in img._getexif().items()
    if k in ExifTags.TAGS
}

GPS = {}
if 'GPSInfo' in exif.keys():
	for key in exif['GPSInfo'].keys():
		decode = ExifTags.GPSTAGS.get(key,key)
		GPS[decode] = exif['GPSInfo'][key]

	ls = ['GPSLongitude','GPSLatitude','GPSLongidudeRef','GPSLatitudeRef']
	if inList(ls, GPS):
		lat = converter(GPS['GPSLatitude'])
		if GPS['GPSLatitudeRef'] != "N":                     
			lat = 0 - lat
		lon = converter(GPS['GPSLongitude'])
		if GPS['GPSLongitudeRef'] != "E":
			lon = 0 - lon
	url = "https://www.google.com.sg/maps/preview#!q="+str(lat)+"%2C"+str(lon)
	webbrowser.open_new_tab(url)