The solution to a modified version of the FizzBuzz challenge.

fizzbuzz2.rb

# Given a number, write a method that outputs the following:
#   when a multiple of 3, output "appy"
#   when a multiple of 5, output "fizz"
#   when a multiple of 3 and 5, output "appy-fizz"
#   Otherwise, output "I'm all good here."

def appyfizz(n)
  s = []
  s << "appy" if n % 3 == 0
  s << "fizz" if n % 5 == 0
  
  s.empty? ? "I'm all good here." : s.join('-')
end