How to convert flat data to structured case classes

Howto.scala

case class B(name: String)

case class A(name: String, seq: Seq[B])

case class X(name: String, seq: Seq[A])

val data: Seq[Tuple3[String, String, String]] = Seq(
  ("X", "Left", "Some value"),
  ("X", "Left", "Some other value"),
  ("X", "Right", "A third value"),
  ("X", "Right", "Fourth value")
)

val structuredData = X("X", Seq(
  A("A", Seq(
    B("Some value"),
    B("Some other value")
  )),
  A("B", Seq(
    B("A third value"),
    B("Fourth value")
  ))
))


println(structuredData)

val structuredByUglyCode = data
  .groupBy(_._1)                                // group by "X"
  .mapValues(_.groupBy(_._2))                   // group by "Left" and "Right"
  .mapValues(_.mapValues(_.map(t => B(t._3))))  // Remove the grouped values from inner-most tuple and map to B
  .mapValues(_.map { case (k, v) => A(k, v) })  // middle layer from `"Left" -> List(B("Some value"), B("Some other value"))` to `A(....)
  .map { case (k, v) => X(k, v.toSeq) }         // Map outer-most layer to List(X(...))