How To Print Integer a Integer Reverse Order Using (Basic Java**)

ReverseInt.java

/**
 *
 * @author Gayan
 */
public class ReverseInt {
    private static int count=1;
    private static boolean found=false;

public static void getnumberofdegits(int number){
  int i=1;
  while(!found){
    if(number<i*10){
    found=true;
    break;

    }
    else{
    i=i*10;
    count++;
  }
 }
}

public static void getreverse(int number){
getnumberofdegits(number);
int modulevalue=10;
int devider=1;
int[] array = new int [count];
   for(int i=0;i<count;i++){
     array[i]=(number%modulevalue)/devider;
     modulevalue=modulevalue*10;
     devider=devider*10;
}
   int printcount=0;
   while(printcount<count){
    System.out.print(array[printcount]);
    printcount++;
    
   }
}
public static void main(String [] args){
int x=12345678;
ReverseInt.getreverse(x);
System.out.println("");

}
}