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December 22, 2015 20:59
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If given integer N and computing from 0 to N, and counting the number of times an integer appears containing a "5". What would be your best solution? Here's what I got. Included in this html document is a web form and some javascript.
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| <HTML> | |
| <HEAD> | |
| <SCRIPT language=Javascript> | |
| //only accept numeric values in input box | |
| function isNumeric(num) | |
| { | |
| var charCode = (num.which) ? num.which : event.keyCode; | |
| if (charCode != 46 && charCode > 31 && (charCode < 48 || charCode > 57)) return false; | |
| return true; | |
| } | |
| //given n calculate how many iterations of numbers containing integer 5 is in the range of 0 to n | |
| function calculateDigitRange() | |
| { | |
| var n = document.forms["form"]["input"].value; | |
| var five_counter = 0 | |
| for (var i=0;i <= (parseInt(n) + 1) ;i++) | |
| { | |
| if (i == (parseInt(n) + 1)) | |
| { | |
| var show = "You gave me the number " + n + "<br><br> I counted from 0 to " + n + "<br><br>and I found numbers containing the integer 5... " + five_counter + " times!" | |
| document.getElementById("answer").innerHTML=show; | |
| break; | |
| } | |
| if (String(i).match(/[5]/) != null) | |
| { | |
| five_counter++; | |
| continue; | |
| } | |
| } | |
| } | |
| </SCRIPT> | |
| <style> | |
| #container {margin:auto; width: 800px; padding-top: 60px;text-align: center;} | |
| .center {text-align: center;} | |
| </style> | |
| </HEAD> | |
| <BODY > | |
| <div id="container"> | |
| <h1>Integer 5 Counter</h1> | |
| <p>Enter a number, I'll count to it from 0, and I'll show you how many times a "5" appears</p> | |
| <form id="form"> | |
| <INPUT id="input" class="center" onKeyPress="return isNumeric(event)" type="text" maxlength="7"> | |
| <br> | |
| <INPUT TYPE="button" VALUE="Enter a number!" onClick="calculateDigitRange()"> | |
| </form> | |
| <p id="answer"></p> | |
| </div> | |
| </BODY> | |
| </HTML> |
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