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Quicksort with standard optimizations
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#include <stdio.h> | |
#include <stdlib.h> | |
static int med3(int a, int b, int c) { | |
return a < b | |
? c < a ? a : (c < b ? c : b) | |
: c > a ? a : (c > b ? c : b); | |
} | |
static void swap(int *a, int i, int j) { | |
int t = a[i]; a[i] = a[j]; a[j] = t; | |
} | |
// Quicksort with median 3 pivot, Dutch national flag partition, and O(log n) stack | |
void sort(int *a, int n) { | |
while (n > 1) { | |
// Non-standard choices for median 3 avoid bad behavior on sorted input. | |
int mid = med3(a[n / 4], a[n / 2], a[3 * n / 4]); | |
int i = 0, j = 0, k = n - 1; | |
while (j <= k) | |
if (a[j] < mid) swap(a, i++, j++); | |
else if (a[j] > mid) swap(a, j, k--); | |
else j++; | |
if (i < n - j) { | |
sort(a, i); | |
a += j; n -= j; | |
} else { | |
sort(a + j, n - j); | |
n = i; | |
} | |
} | |
} | |
int main(void) { | |
int n = 1000000, a[n]; | |
for (int i = 0; i < n; ++i) a[i] = random() % 1000; | |
sort(a, n); | |
for (int i = 0; i < n; ++i) printf("%d\n", a[i]); | |
return 0; | |
} |
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