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from random import choice, shuffle | |
from collections import Counter | |
symbols = "abcdefghijklmnopqrstuvwxyz" | |
def gen_random_string(N): | |
""" | |
Generates a random string | |
""" | |
return ''.join(choice(symbols) for _ in range(N)) | |
def normalize(res_dict): | |
""" | |
Может получиться так, что осталось добавить один символ, но все буквы уже встречаются нечетное кол-во раз | |
поэтому я решил вырезать все вхождения первой буквы и плюсовать их ко второй, ну и +1, чтоб получить нужную длину | |
""" | |
tmp = list(res_dict.keys()) | |
tmp.sort() | |
if res_dict and list(symbols) == tmp: | |
res_dict[list(res_dict.keys())[1]] = res_dict.pop(list(res_dict.keys())[0]) + 1 | |
def gen_odd_string(N, res_dict): | |
""" | |
Generates a string with an odd number of occurrences of characters | |
""" | |
s = gen_random_string(N) | |
c = Counter(s) | |
print(f"Counter: {c}") | |
# qwe(res_dict) | |
for symbol, frequency in c.items(): | |
res_dict[symbol] = res_dict.get(symbol, 0) + frequency | |
for symbol, frequency in res_dict.items(): | |
print(f"DEBUG: symbol: {symbol}, frequency {frequency}") | |
res_dict[symbol] = frequency - 1 if frequency % 2 == 0 else frequency | |
print(res_dict) | |
return "".join(i for i in [k * v for k, v in res_dict.items()]) | |
def solution(N): | |
# write your code in Python 3.6 | |
res_dict = {} | |
result = gen_odd_string(N, res_dict) | |
print(f"LEN: {len(result)}") | |
while len(result) != N: | |
result = gen_odd_string(N - len(result), res_dict) | |
print(f"LEN: {len(result)}") | |
if len(result) == N - 1: | |
normalize(res_dict) | |
break | |
# Shuffle string | |
tmp_list = list(result) | |
shuffle(tmp_list) | |
return ''.join(tmp_list) |
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