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/// https://www.hackerrank.com/challenges/gem-stones/problem | |
/// | |
/// There is a collection of rocks where each rock has various minerals embedded in it. Each type of mineral is designated by a lowercase letter in the range . | |
/// There may be multiple occurrences of a mineral in a rock. A mineral is called a gemstone if it occurs at least once in each of the rocks in the collection. | |
/// | |
int calcGemStones(List<String> input) { | |
var map = {}; | |
// go over the input collection and calculate amount of string where the character is present | |
// In order not to count "aaa" as three times we maintain ignoreSet set | |
for (var string in input) { | |
Set ignoreSet = {}; | |
for (var i = 0; i < string.length; i++) { | |
if (ignoreSet.contains(string[i])) { | |
continue; | |
} | |
// init in case value is new | |
map[string[i]] ??= 0; | |
map[string[i]] += 1; | |
// remember the character and ignore it in next loops | |
ignoreSet.add(string[i]); | |
} | |
} | |
var length = input.length; | |
// if amount of appearances is equal to amount of input strings | |
// then we found a gem and add +1 to counter | |
return map.values.fold<int>(0, (previousValue, element) { | |
if (element == length) { | |
previousValue++; | |
} | |
return previousValue; | |
}); | |
} | |
void main() { | |
var input = ["abc", "bc", "cba"]; | |
print("Gem stones"); | |
print(calcGemStones(input)); // 2 | |
input = ['abcdde', 'baccd', 'eeabg']; // 2 | |
print(calcGemStones(input)); | |
input = ['basdfj', 'asdlkjfdjsa', 'bnafvfnsd', 'oafhdlasd']; // 4 | |
print(calcGemStones(input)); | |
input = ['a', 'b', 'c', 'd']; // 0 | |
print(calcGemStones(input)); | |
input = ['a', 'ab', 'ca', 'dddbbbbbcaccd']; // 1 | |
print(calcGemStones(input)); | |
} |
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