백준 4344번 평균은 넘겠지

4344.cpp

#include <iostream>
using namespace std;

int main(void){
    int arr[1000] = {0,};
    int cycle = 0, snum = 0, sum = 0, avg = 0;
    
    cin >> cycle;
    for(int i = 0; i < cycle; ++i){
        cin >> snum;
        for(int j = 0; j < snum; ++j){
            cin >> arr[j];
        }
        for(int k = 0; k < snum; ++k){
            sum += arr[k];
        }
        avg = sum/snum;
        int cnt = 0;
        for(int l = 0; l < snum; ++l){
            if(arr[l] > avg) ++cnt;
        }
        /*  이렇게도 가능하다.
         cout.precision(3);
         cout << (double)cnt/snum*100 << "%" << endl;
         */
        printf("%.3f%%\n", (double)cnt/snum*100);
        sum = 0;
        avg = 0;
    }
    
    return 0;
}